In topology, a second-countable space is a topological space that admits a countable basis for its topology, meaning there exists a countable collection of open sets such that every open set in the topology can be expressed as a union of sets from this collection.[1] This countability axiom, also known as the second countability axiom, distinguishes such spaces from those requiring uncountably many basis elements to generate their open sets.[2]Second-countable spaces possess several key properties that make them central to many results in general topology. They are necessarily first-countable, meaning every point has a countable local basis of neighborhoods, and separable, possessing a countable dense subset.[1] Moreover, every open cover of a second-countable space admits a countable subcover, rendering the space Lindelöf.[2] Subspaces of second-countable spaces are second-countable, as are countable products of such spaces, which facilitates the study of structured topological constructions.[1]In metric spaces, second-countability is equivalent to both separability and the Lindelöf property, highlighting its role in bridging abstract topology with metric geometry.[2] A prominent application is Urysohn's metrization theorem, which states that any regular Hausdorff second-countable space is metrizable, allowing the import of metric tools into more general settings.[2]Classic examples include the Euclidean spaces \mathbb{R}^n with the standard topology, where open balls centered at points with rational coordinates and rational radii form a countable basis.[3] In contrast, an uncountable discrete space fails to be second-countable, as its singleton sets form an uncountable basis.[1]
Definition and basics
Formal definition
A topological space (X, \tau) is second-countable if it satisfies the second axiom of countability: there exists a countable collection \mathcal{B} = \{B_n \mid n \in \mathbb{N}\} of open sets in \tau such that every open set U \in \tau can be written as a union U = \bigcup_{i \in I} B_i for some index set I \subseteq \mathbb{N}.[1] This collection \mathcal{B} is called a countable basis for the topology \tau.[1]The second axiom of countability strengthens the first axiom of countability, which requires only that each point x \in X has a countable local basis consisting of neighborhoods of x.[1] Every second-countable space is first-countable, but the converse does not hold in general.[1]Second-countability imposes a form of global simplicity on the topology, ensuring that the structure can be described using only countably many basic open sets.[4]
Countable basis
A basis for a topology on a set X is a collection \mathcal{B} of open subsets of X such that every open set in the topology can be expressed as a union of elements from \mathcal{B}.[1][4]For \mathcal{B} to qualify as a basis, it must satisfy the condition that for every open set U in the topology and every point x \in U, there exists an element B \in \mathcal{B} such that x \in B \subseteq U.[1][5]In the context of second-countable spaces, the basis \mathcal{B} is required to be countable, meaning it has cardinality \aleph_0, which ensures that the topology is generated by a countably infinite family of open sets.[4][6]A related concept is that of a subbasis, which is a collection of open sets whose finite intersections form a basis for the topology; notably, if a space admits a countable subbasis, then it possesses a countable basis, though the full construction via countable unions of finite intersections is omitted here.[4][5]
Properties
Implied countability axioms
A second-countable space satisfies several important countability axioms as direct consequences of possessing a countable basis. In particular, every such space is separable, meaning it contains a countable dense subset. To see this, let \{B_n \mid n \in \mathbb{N}\} be a countable basis for the topology. For each n such that B_n \neq \emptyset, select a point x_n \in B_n. The set D = \{x_n \mid B_n \neq \emptyset\} is countable, and it is dense because every non-empty open set U contains some basis element B_k \subseteq U, so x_k \in U.[7][8]Similarly, every second-countable space is Lindelöf, meaning that every open cover admits a countable subcover. Let \{B_n \mid n \in \mathbb{N}\} be a countable basis and \{U_\alpha\}_{\alpha \in A} an open cover of X. Consider the countable subcollection of basis elements \{B_n \mid B_n \subseteq U_\alpha \text{ for some } \alpha\}. This collection covers X, since for any x \in X, there exists some B_k \ni x with B_k \subseteq U_{\alpha(x)} for some \alpha(x). The corresponding \{U_\alpha\} then form a countable subcover.[9]Moreover, every second-countable space is first-countable. For any point x \in X, the collection \mathcal{B}_x = \{B_n \mid x \in B_n\} forms a countable local basis at x, as it is a countable subcollection of the basis and any open neighborhood U of x contains some B_k \ni x with B_k \subseteq U. This countable local basis ensures that the space satisfies the first-countability axiom at every point.[10]These implications hold in general topological spaces and rely on the countability of the basis for their proofs, without requiring additional axioms like metrizability. The construction of the dense set D in the separability proof, for instance, uses the axiom of countable choice to select points from each non-empty basis element, though this is often assumed in standard developments of topology.[7]
Separation and metrizability
A second-countable regular Hausdorff topological space is metrizable. This result is known as Urysohn's metrization theorem.[11]The proof begins by noting that second-countability and regularity together imply normality. Let \{B_n : n \in \mathbb{N}\} be a countable basis for X. For each pair (m,n) such that \overline{B_m} \subseteq B_n, Urysohn's lemma (applicable due to normality) yields a continuous function g_{m,n}: X \to [0,1] with g_{m,n} \equiv 1 on \overline{B_m} and g_{m,n} \equiv 0 on X \setminus B_n. Enumerate these pairs to obtain a countable family of such functions \{f_k : X \to [0,1] : k \in \mathbb{N}\}. The map F: X \to [0,1]^\mathbb{N} defined by F(x) = (f_k(x))_{k \in \mathbb{N}} is continuous because each coordinate is continuous and the product topology is used. Injectivity follows since for distinct x, y \in X, there exists a basis element containing x but not y, ensuring some f_k(x) \neq f_k(y). Finally, F is an open embedding, as preimages of basis elements in the image can be refined using the functions to show openness. Since [0,1]^\mathbb{N} is metrizable (e.g., via the metric d((a_k),(b_k)) = \sum 2^{-k} |a_k - b_k|), so is X.[11]Second-countability combined with the Hausdorff axiom T_2 alone does not suffice for metrizability, as there exist second-countable Hausdorff spaces that fail regularity. A standard example is the K-topology on \mathbb{R}, where K = \{1/n : n \in \mathbb{N}\} and the basis consists of all open intervals (a,b) together with sets of the form (a,b) \setminus K. This topology is Hausdorff, as it refines the standard topology on \mathbb{R}, and second-countable, inheriting a countable basis from the standard one augmented by countably many sets removing K. However, it is not regular: the point $0 and the closed set K cannot be separated by disjoint open neighborhoods, since any neighborhood of $0 intersects K and any neighborhood of points in K will intersect such a neighborhood of $0. Thus, this space is not metrizable.[12]Second-countable regular spaces are paracompact: every open cover admits a locally finite open refinement. Since second-countability implies the space is Lindelöf (every open cover has a countable subcover), and regular Lindelöf spaces are paracompact by Morita's theorem, the result follows. In particular, second-countable regular Hausdorff spaces, being metrizable, inherit paracompactness from metric spaces.[13]
Cardinality and density
A second-countable space has at most $2^{\aleph_0} open subsets, as each open set is a union of elements from a countable basis, and the set of all subsets of a countable collection has cardinality equal to the continuum.[14]In a T_1 second-countable space, the cardinality is at most the continuum $2^{\aleph_0}. This bound arises because points are distinguished by their neighborhood systems relative to the countable basis \{B_n\}_{n \in \mathbb{N}}: for each point x, the set S_x = \{n \in \mathbb{N} \mid x \in B_n\} is a subset of \mathbb{N}, yielding at most $2^{\aleph_0} possible such sets; under T_1, distinct points have distinct S_x, providing an injection from the space into the power set of \mathbb{N}. For Hausdorff second-countable spaces, the same cardinality bound holds.[15]Every second-countable space admits a countable dense subset. Given a countable basis \{U_n \mid n \in \mathbb{N}\}, select a point x_n \in U_n for each n, and let D = \{x_n \mid n \in \mathbb{N}\}. This D is countable. To see density, consider any nonempty open set V; it contains some basis element U_k, so x_k \in V \cap D.[5][1]Second-countability is hereditary: any subspace of a second-countable space inherits a countable basis. If \{B_n\}_{n \in \mathbb{N}} is a countable basis for the ambient space X, then \{B_n \cap Y \mid n \in \mathbb{N}, B_n \cap Y \neq \emptyset\} forms a countable basis for the subspace Y. Consequently, every subspace has a countable dense subset.[1]The product of two second-countable spaces is second-countable. If \{B_n\}_{n \in \mathbb{N}} and \{C_m\}_{m \in \mathbb{N}} are countable bases for X and Y, respectively, then \{B_n \times C_m \mid n, m \in \mathbb{N}\} is a countable basis for X \times Y. This extends to countable products of second-countable spaces.[1]
Examples
Positive examples
Euclidean spaces provide a fundamental example of second-countable topological spaces. For \mathbb{R}^n equipped with the standard Euclidean topology, a countable basis consists of all open balls centered at points with rational coordinates and having rational radii. Since the set of points in \mathbb{Q}^n is countable and the positive rational numbers are countable, the collection of such balls is a countable family that generates the topology.[16][10]More generally, any separable metric space is second-countable. In a separable metric space (X, d), there exists a countable dense subset D \subseteq X. The open balls centered at points of D with rational radii form a countable basis for the topology, as every open set in X can be expressed as a union of such balls. This equivalence between separability and second-countability holds specifically for metric spaces, distinguishing them from more general topological spaces.[17][18]Countable discrete spaces also satisfy second-countability. In a discrete topology on a countable set X, the singletons \{x\} for each x \in X serve as a basis, and since X is countable, this basis is countable. Uncountable discrete spaces fail this property, but the countable case aligns directly with the definition.Function spaces like the space of continuous real-valued functions C[0,1] on the closed interval [0,1], endowed with the supremum norm, are second-countable due to their separability as metric spaces. The set of polynomials with rational coefficients forms a countable dense subset, allowing the construction of a countable basis via open balls around these polynomials with rational radii. This separability ensures the space inherits second-countability from its metric structure.[19]
Counterexamples
The uncountable discrete space provides a basic counterexample to second-countability. Consider an uncountable set X equipped with the discrete topology, where every subset is open. A basis for this topology consists of all singletons \{x\} for x \in X, which form an uncountable collection. Thus, no countable basis exists, and the space fails to be second-countable.[20] This example also illustrates the failure of separability, as any dense subset must intersect every nonempty open set, requiring it to be the entire uncountable X.[20]The Sorgenfrey line, or real line with the lower limit topology, is another standard counterexample. The topology on \mathbb{R} is generated by the basis \mathcal{B} = \{[a, b) \mid a < b, a, b \in \mathbb{R}\}, which is uncountable due to the continuum many choices for a. To see that no countable basis suffices, suppose \{U_n\}_{n=1}^\infty is a countable collection of open sets forming a basis. For each r \in \mathbb{R}, the basic open set [r, r+1) must contain some U_n with r \in U_n \subseteq [r, r+1). Each such U_n must have infimum exactly r, since U_n \subseteq [r, r+1) implies inf U_n \geq r, and r \in U_n with U_n open implies U_n contains [r, s) for some s > r, so inf U_n = r. Thus, distinct r require distinct U_n with different infima, making the map r \mapsto n injective from the uncountable \mathbb{R} to \mathbb{N}, a contradiction. Hence, the Sorgenfrey line is not second-countable.[21] Despite this, it is first-countable and separable, with the rationals dense.[21]The long line offers a more sophisticated counterexample, resembling a manifold but failing second-countability. Constructed as the set \omega_1 \times [0,1), ordered lexicographically and equipped with the order topology—where \omega_1 is the least uncountable ordinal—it is a connected, locally Euclidean Hausdorff space. However, it lacks a countable basis: any basis must distinguish uncountably many disjoint open intervals corresponding to the ordinal structure, exceeding countability.[22] The long line is also not separable, as no countable subset can be dense in its uncountable length.[22]The Moore plane (or Niemytzki plane) demonstrates that separability does not imply second-countability. This space is the upper half-plane including the x-axis, with the usual Euclidean topology on the open upper half-plane and basis elements at x-axis points p given by \{p\} \cup D, where D is a disk in the upper half-plane tangent at p. It is separable, with the set of points with rational coordinates dense. Yet, the subspace topology on the uncountable x-axis yields uncountably many isolated points (singletons open in the subspace), requiring an uncountable basis for the whole space. Thus, the Moore plane is not second-countable.[20] It is first-countable but fails metrizability.[20]