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Closed set

In topology, a closed set is a subset of a topological space whose complement is an open set. Equivalently, a set is closed if it contains all its limit points. In first-countable spaces such as metric spaces, it is closed if the limit of every convergent sequence in the set belongs to the set. Closed sets exhibit key properties that mirror those of open sets in complementary fashion: the and the entire space are closed, arbitrary intersections of closed sets are closed, and finite unions of closed sets are closed. In metric spaces, common examples include closed balls, which consist of all points at a less than or equal to a fixed from a center, as well as the integers within the real numbers under the standard . These concepts are foundational in and , enabling the study of , , and without relying on specific metrics. Sets that are both open and closed, termed clopen sets, arise in disconnected spaces and play a role in understanding topological connectedness.

Core Concepts

Definition

In , a C of a X is defined as closed if its complement X \setminus C is open. Equivalently, C is closed if it contains all of its limit points. A point p \in X is a limit point of C if every open neighborhood of p intersects C at some point other than p itself. This condition ensures that C encompasses all points that are "arbitrarily close" to it in the topological sense, without relying on distances. The definition assumes familiarity with the basic structure of topological spaces, where open sets form a collection closed under arbitrary unions and finite intersections, and neighborhoods are open sets containing a given point. The concept of closed sets originated in the early 20th-century development of , particularly through Hausdorff's work, which generalized notions from metric spaces to abstract topological spaces. In his 1914 book Grundzüge der Mengenlehre, Hausdorff introduced closed sets as foundational elements, defined axiomatically to preserve topological invariance and overcome the restrictions of metric-based approaches, such as those limited to Euclidean spaces. This framework allowed for the study of and in broader settings.

Relation to Open Sets

In any topological space, the collection of closed sets forms precisely the family of complements of open sets, establishing a fundamental duality between the two concepts. Specifically, a C of the space X is closed its complement X \setminus C is open. This equivalence arises directly from the definition of a , where the open sets satisfy the s of including the and the whole , being closed under arbitrary unions, and closed under finite intersections; the corresponding properties for closed sets—containing the and whole , closed under arbitrary intersections, and closed under finite unions—follow by taking complements. This duality ensures that the is inherently closed under complements, meaning that the complement of any is closed and vice versa, which is a key structural underpinning the theory of . A special case of this duality occurs with , which are subsets that are simultaneously open and closed. The \emptyset and the entire X are always clopen in any , as their complements are each other and both satisfy the axioms. In general, clopen sets represent that respect the without boundaries in the open-closed sense. In connected topological spaces, this duality takes on added significance: the only clopen sets are \emptyset and X itself. A is connected if it cannot be expressed as the of two nonempty disjoint open sets, which equivalently means it admits no nontrivial clopen subsets; any proper nonempty clopen set would disconnect the space by serving as both an open and closed . This uniqueness highlights the role of connectedness in restricting the duality's manifestations. The open- duality also lays the groundwork for concepts like the interior and of a set, where the interior is the largest open contained within it, and the can be intuitively viewed as the difference between the (the smallest set containing it) and the interior, though these are explored further elsewhere. This relation reinforces the symmetric framework of , allowing proofs and properties to be dualized by complementation.

Properties

Set Operations

In topological spaces, closed sets exhibit specific algebraic properties under set operations, forming a family that is stable under certain unions and intersections. The collection of all closed sets in a topological space X is closed under arbitrary intersections and finite unions, meaning the result of such an operation remains closed. This stability arises from the duality between closed sets and open sets, where a set is closed its complement is open. The of any collection of closed sets, whether finite or infinite, is itself closed. To see this, suppose \{F_i : i \in I\} is an arbitrary family of closed subsets of X. Then the complements \{F_i^c : i \in I\} are open sets. The complement of the intersection is given by \left( \bigcap_{i \in I} F_i \right)^c = \bigcup_{i \in I} F_i^c, which is open as an arbitrary union of open sets. Therefore, \bigcap_{i \in I} F_i is closed. In contrast, the union of finitely many closed sets is closed, but arbitrary (infinite) unions need not be. For a finite collection \{F_1, \dots, F_n\} of closed sets, the complements \{F_1^c, \dots, F_n^c\} are open, and the complement of the is \left( \bigcup_{k=1}^n F_k \right)^c = \bigcap_{k=1}^n F_k^c, a finite of open sets, which is open. Thus, \bigcup_{k=1}^n F_k is closed. However, in spaces such as the real numbers with the standard , an union of closed sets may fail to be closed. These properties distinguish closed sets from open sets, which are instead closed under arbitrary unions but only finite intersections.

Closure Operator

In a (X, \tau), the of a A \subseteq X, denoted \mathrm{cl}(A) or \overline{A}, is defined as the of all closed sets in X that contain A. This makes \mathrm{cl}(A) the smallest closed set containing A with respect to inclusion. Equivalently, \mathrm{cl}(A) = A \cup A', where A' is the set of all limit points of A. The closure operator \mathrm{cl} satisfies three fundamental properties: it is extensive, idempotent, and monotonic. Extensiveness: For any A \subseteq X, A \subseteq \mathrm{cl}(A).
Proof: By definition, \mathrm{cl}(A) is the of all closed sets containing A. Each such closed set contains A, so their intersection also contains A. Thus, A \subseteq \mathrm{cl}(A).
Monotonicity: If A \subseteq B \subseteq X, then \mathrm{cl}(A) \subseteq \mathrm{cl}(B).
Proof: The family of closed sets containing B is a of the family of closed sets containing A, since any closed set containing B also contains A. The over a smaller family yields a larger or equal set, so \mathrm{cl}(B) \supseteq \mathrm{cl}(A).
Idempotence: For any A \subseteq X, \mathrm{cl}(\mathrm{cl}(A)) = \mathrm{cl}(A).
Proof: First, \mathrm{cl}(A) \subseteq \mathrm{cl}(\mathrm{cl}(A)) by extensiveness. For the reverse inclusion, note that \mathrm{cl}(A) is closed (as an intersection of closed sets) and contains A, so it is one of the closed sets in the intersection defining \mathrm{cl}(A). Thus, \mathrm{cl}(A) \supseteq \mathrm{cl}(\mathrm{cl}(A)), since \mathrm{cl}(\mathrm{cl}(A)) is the smallest closed set containing \mathrm{cl}(A), and \mathrm{cl}(A) is already closed and contains itself. Combining both directions gives equality.
A subset A \subseteq X is closed if and only if \mathrm{cl}(A) = A. If A is closed, then \mathrm{cl}(A) = A by the definition of closure as the smallest closed set containing A. Conversely, if \mathrm{cl}(A) = A, then A equals its closure, which is always closed as an intersection of closed sets, so A is closed. The closure operator in a topological space satisfies the Kuratowski closure axioms, which provide a complete axiomatic characterization. These four axioms, formulated by Kazimierz Kuratowski, are:
  1. \mathrm{cl}(\emptyset) = \emptyset (the empty set has empty closure).
  2. A \subseteq \mathrm{cl}(A) for all A \subseteq X (extensiveness).
  3. \mathrm{cl}(\mathrm{cl}(A)) = \mathrm{cl}(A) for all A \subseteq X (idempotence).
  4. \mathrm{cl}(A \cup B) = \mathrm{cl}(A) \cup \mathrm{cl}(B) for all A, B \subseteq X (additivity).
    Any operator satisfying these axioms defines a unique topology on X via the closed sets as the fixed points of the operator (sets A with \mathrm{cl}(A) = A). Monotonicity follows as a theorem from axioms 2 and 4.

Examples

Standard Topological Spaces

In the real line \mathbb{R} equipped with the standard topology generated by open intervals, closed intervals of the form [a, b] where a \leq b are closed sets, as their complements (-\infty, a) \cup (b, \infty) consist of open intervals and are thus open. The set of integers \mathbb{Z} is also closed in this topology, since its complement \mathbb{R} \setminus \mathbb{Z} is a union of open intervals (n, n+1) for n \in \mathbb{Z}, making the complement open. Singletons \{x\} for x \in \mathbb{R} are closed, as their complements \mathbb{R} \setminus \{x\} are open, being the union of (-\infty, x) and (x, \infty). In Euclidean spaces \mathbb{R}^n with the standard topology induced by the Euclidean metric, closed balls \{x \in \mathbb{R}^n : \|x - c\| \leq r\} for center c \in \mathbb{R}^n and radius r > 0 are closed sets, containing all their limit points. Hyperplanes, defined as affine subspaces of n-1, such as \{x \in \mathbb{R}^n : a \cdot x = b\} for a \neq 0 and b \in \mathbb{R}, are closed, as they are the inverse images of singletons under continuous linear functionals. Compact subsets like the n-spheres S^n = \{x \in \mathbb{R}^{n+1} : \|x\| = 1\} are closed in \mathbb{R}^{n+1}, since compact sets in Hausdorff spaces are closed. In the discrete topology on a set X, where every subset is open, every subset is also closed, as the complement of any subset is open by definition. Conversely, in the on X, the only open sets are \emptyset and X, so the only closed sets are also \emptyset and X, with all proper nonempty subsets neither open nor closed. These examples illustrate how closed sets depend on the , with the operator verifying that a set equals its closure in these cases.

Metric and Normed Spaces

In metric spaces, a subset C is closed if and only if it contains the limit of every convergent sequence with terms in C. This sequential characterization arises because metric spaces are first-countable, meaning each point has a countable neighborhood basis, allowing sequences to detect limit points effectively. To see the equivalence, suppose C is closed; then its complement is open, so if a sequence in C converges to x, x cannot lie in the complement, hence x \in C. Conversely, if C is not closed, there exists a limit point x \notin C; since the metric induces a first-countable topology, a sequence in C can be constructed converging to x, contradicting the assumption. This proof leverages the completeness of Cauchy sequences in the ambient space only indirectly, as convergence in metric spaces implies the sequence is Cauchy, but the characterization holds for any metric space, complete or not. An equivalent distance-based characterization states that C is closed if for every x \notin C, there exists \varepsilon > 0 such that the open ball B(x, \varepsilon) intersects C emptily. This formulation directly ties to the openness of the complement: the empty intersection ensures B(x, \varepsilon) \subseteq X \setminus C, confirming no sequence from C can approach x. In metric spaces, these criteria generalize the topological notion of closed sets by exploiting the metric's structure for explicit constructions via distances and sequences. In normed vector spaces, where the metric is induced by the norm d(x, y) = \|x - y\|, closed sets retain the sequential characterization: a subspace is closed if it contains limits of all convergent sequences within it. For instance, the closed unit ball \{x : \|x\|_p \leq 1\} in the \ell^p spaces (for $1 \leq p \leq \infty) is closed, as it is the preimage of the closed interval [0, 1] under the continuous norm function. Unlike general topological spaces, where sequential criteria may fail in non-first-countable settings, the metric from the norm ensures such equivalences hold reliably.

Advanced Relations

Complementarity and Boundaries

In , the of a A of a X, denoted \partial A, is defined as the of the of A and the of its complement: \partial A = \mathrm{cl}(A) \cap \mathrm{cl}(X \setminus A). This captures the points that serve as the interface between A and its complement. Equivalently, a point x \in X belongs to \partial A if every open neighborhood of x intersects both A and X \setminus A. A subset A \subseteq X is closed it contains its , that is, \partial A \subseteq A. This condition ensures that all limit points on the "edge" of A are included within A itself, aligning with the definition of closed sets as those containing all their limit points. In contrast, a set A is open its is disjoint from it: \partial A \cap A = \emptyset. Here, no boundary points lie inside A, meaning every point in A has a neighborhood entirely contained within A. The term "" is often used as a synonym for in topological contexts, emphasizing the same set-theoretic . In the study of manifolds, the acquires additional structure: a manifold with is a locally homeomorphic to either or a closed half-space, where the consists of those points homeomorphic to the "" of the half-space, such as \mathbb{R}^{n-1} \times \{0\}. These components represent the "edges" or limiting surfaces of the manifold, distinct from interior points. Points of adherence of a set A, also known as the \mathrm{cl}(A), include all points where neighborhoods intersect A; the \partial A specifically highlights those adherence points shared with the complement, underscoring the closed set's inclusion of such interfaces.

Connections to Compactness and Continuity

In any , a of a is compact. To see this, let K be a compact of a X, and let C \subseteq K be closed in X. Consider an open cover \{U_\alpha\} of C. Since C is closed, its complement X \setminus C is open. The collection \{U_\alpha\} \cup \{X \setminus C\} then forms an open cover of K. By compactness of K, there exists a finite subcover, say U_1, \dots, U_n and possibly X \setminus C. Removing X \setminus C if present yields a finite subcover of C, proving C compact. A fundamental characterization of continuity in topology states that a function f: X \to Y between topological spaces is continuous if and only if the preimage f^{-1}(V) of every closed set V \subseteq Y is closed in X. This is equivalent to the more common definition that the preimage of every open set in Y is open in X, since the complement of a closed set is open and preimages preserve complements: if V is closed, then Y \setminus V is open, so f^{-1}(Y \setminus V) = X \setminus f^{-1}(V) is open, implying f^{-1}(V) is closed. This closed-set criterion provides an alternative perspective on continuity, emphasizing preservation of closure under preimages, which is particularly useful in proofs involving limits or closures. In Hausdorff topological spaces, every compact subset is closed. To prove this, let X be Hausdorff and K \subseteq X compact. For any x \in X \setminus K, the Hausdorff property ensures that for each y \in K, there exist disjoint open neighborhoods U_y of x and V_y of y. The collection \{V_y : y \in K\} covers K, so by compactness, a finite subcollection V_{y_1}, \dots, V_{y_n} covers K. Then U = \bigcap_{i=1}^n U_{y_i} is an open neighborhood of x disjoint from K, showing X \setminus K is open and thus K closed. The converse—that every closed set is compact—does not hold in general but is true in specific settings, such as finite-dimensional via the . In metric spaces, compactness is closely tied to sequential compactness, where a set is sequentially compact if every sequence has a convergent subsequence. For the Euclidean space \mathbb{R}^n with the standard metric, the Heine-Borel theorem asserts that a subset is compact if and only if it is closed and bounded. One direction follows from general properties: compact sets in metric spaces are closed (as limits of convergent sequences lie in the set) and bounded (by covering with balls of fixed radius and using finite subcovers). The converse requires a proof sketch: assume K \subseteq \mathbb{R}^n is closed and bounded, so it lies in some closed ball \overline{B(0, R)}. Proceed by induction on dimension. For n=1, consider an open cover \{U_\alpha\} of [a, b]. Let S = \{x \in [a, b] \mid [a, x] admits a finite subcover from \{U_\alpha\}\}. Let t = \sup S. Some U_\beta contains t and an interval (t - \epsilon, t + \epsilon) for \epsilon > 0. Then [a, t + \epsilon/2] admits a finite subcover, implying t = b and thus [a, b] has a finite subcover. For higher n, project onto coordinate hyperplanes and use induction, ensuring the projection's finite cover lifts back via closedness. This sequential compactness in \mathbb{R}^n underpins many applications in analysis, such as uniform continuity on compact sets.

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