Fact-checked by Grok 2 weeks ago
References
-
[1]
Section 10.12 (00CV): Tensor products—The Stacks projectThe R-module T which satisfies the above universal property is called the tensor product of R-modules M and N, denoted as M \otimes _ RN.
-
[2]
[PDF] TENSOR PRODUCTS 1. Introduction Let R be a commutative ring ...The quotient module by D will serve as the tensor product: set. M ⊗R N := FR(M × N)/D. We write the coset δ(m,n) + D in M ⊗R N as m ⊗ n. From the definition of ...
-
[3]
[PDF] 1. The Tensor Product - Berkeley MathThe Tensor Product. Tensor products provide a most “natural” method of combining two modules. They may be thought of as the simplest way to combine modules ...
-
[4]
[PDF] Notes on Tensor Products - Brown MathMay 3, 2014 · Basic Definition: Let R be a commutative ring with 1. A (unital) R-module is an abelian group M together with a operation R × M → M, ...
-
[5]
[PDF] Algebraic Topology I: Lecture 20 Tensor ProductDefinition 20.3. Let M, N be R-modules. A tensor product of M and N is an R-module P and a bilinear map β0 : M ×N → P such that for every R-bilinear map β ...
-
[6]
[PDF] Notes on tensor products Robert Harron - Department of MathematicsBasic definition. Last semester, we quickly defined and constructed the tensor product of modules two modules M and N over a commutative ring R, defining it as ...
-
[7]
Tensor product-definition-balanced versus bilinear mapsDec 10, 2014 · On the other hand, in the general case, for noncommutative rings one has to use balanced maps M×N→Z instead of bilinear. Of course, in the ...Missing: advantages | Show results with:advantages
-
[8]
[PDF] Notes on Tor and Ext - UChicago MathThus, in general, M ⊗R N is only an Abelian group. When R is commutative, all of our functors take values in the category of. R-modules rather than just Abelian ...
-
[9]
[PDF] Homological Algebra - Purdue MathHomological algebra is a rich area, often studied with modules over commutative rings. A complex is a collection of groups (or left modules) and homomorphisms.
-
[10]
Tor in nLabOct 9, 2024 · In the context of homological algebra, the Tor Tor -functor is the derived tensor product: the left derived functor of the tensor product of R ...Missing: via | Show results with:via
- [11]
- [12]
-
[13]
Section 17.16 (01CA): Tensor product—The Stacks projectThe tensor product of modules M, N over a ring R satisfies symmetry, namely M \otimes _ RN = N \otimes _ RM, hence the same holds for tensor products of ...
-
[14]
Tensor product of modules; isomorphisms - Abstract AlgebraAug 30, 2022 · Let R be a commutative ring with identity, and let M,N be R -modules. Let I,J be ideals of R, and let S be a multiplicatively closed subset of R such that 1 \ ...
-
[15]
Section 15.22 (0549): Torsion free modules—The Stacks projectWe say M is torsion free if the only torsion element of M is 0. We say M is a torsion module if every element of M is torsion.
-
[16]
tensor product of algebras in nLabAug 24, 2020 · We write also A ⊗ R B A \otimes_R B for the tensor product of algebras. For commutative R R -algebras, the tensor product is the coproduct in ...
-
[17]
[PDF] Given vector spaces V and W over k one can define a new vector ...Jul 8, 2017 · V ⊗W, the tensor product of V and W, is a new vector space with a basis of {ei ⊗fj}i∈I, j∈J, and is the "product" of vector spaces.
-
[18]
[PDF] Modules - OSU MathFeb 20, 2024 · Let m, n ∈ N. The tensor product Rm ⊗Rn of free modules Rm and Rn is isomorphic to (R⊗R)mn ∼= Rmn. The standard basis in Rm ⊗ Rn is ei ⊗ e′.<|separator|>
-
[19]
[PDF] Tensor Products of Abelian Groups1Z/mZ⊗Z/nZ. ∼. = Z/dZ where d = gcd(m, n). Proof. Let h(a⊗b) = ab mod d. It extends to a homomor- phism since (a, b) → ab mod d is bilinear. It is onto ...
-
[20]
[PDF] Z/p ⊗Z/pq Z/qJan 14, 2009 · [19.5] Compute Q ⊗Z Q. We claim that this tensor product is isomorphic to Q, via the Z-linear map β induced from the Z-bilinar.Missing: _ℤ gcd(
-
[21]
[PDF] tensor products ii - keith conradThe tensor product construction of the polynomial ring over R in n non- commuting indeterminates is quite different from that of the tensor product construction.
-
[22]
NoneBelow is a merged summary of tensor fields based on the provided segments from "Introduction to Smooth Manifolds" by John M. Lee and the document at https://kashanu.ac.ir/Files/smooth%20manifold-lee.pdf. To retain all information in a dense and organized manner, I will use a combination of narrative text and a table in CSV format for detailed comparisons across sections. The narrative will provide an overview, while the table will capture specific details such as definitions, coordinate expressions, physics examples, and direct quotes with page references.
-
[23]
[PDF] Field Theory in Curved Spacetime and the Stress-Energy TensorDec 12, 2020 · According to Einstein's theory of gravity, the graviton is affected by energy and momentum. Next, the stress-energy tensor is defined as follows ...
-
[24]
Vector Space Tensor Product -- from Wolfram MathWorldThe tensor product of two vector spaces V and W, denoted V tensor W and also called the tensor direct product, is a way of creating a new vector space ...
-
[25]
[PDF] Introduction to Commutative AlgebraTENSOR PRODUCT OF MODULES 25. Let T = C/D. For each basis element (x, y) of C, let xy denote its image in T. Then T is generated by the elements of the form ...
-
[26]
[PDF] EXTENSION AND RESTRICTION OF SCALARS Let fThis is very confusing, however, since V 0 is a complex vector space, whereas f∗(V 0) is a real vector space. If V is a real vector space, then so is f∗(VC), ...
-
[27]
[PDF] Descent TheoryThis algebra is worked out in this section. No Noetherian or finiteness conditions on either rings or modules are required. We are concerned with an arbitrary ...
-
[28]
[PDF] Semisimplicity and Tensor Products of Group RepresentationsSince Sym2 V is assumed to be semisimple, so is V F. This means that V becomes semisimple after the base change F: k ª k. By an elementary. Žw x.<|control11|><|separator|>
-
[29]
[PDF] Representation Theory - Berkeley MathThis allows an effective calculus with group representations, including their tensor products, and their decomposition into irreducibles. We want to attach ...
-
[30]
[PDF] Introduction to Commutative Algebra - OSU MathApr 8, 2008 · Free modules are flat, so the middle row is exact. Clearly the ... , Commutative algebra. Vol. II, The University Series in Higher.
-
[31]
[PDF] Hideyuki Matsumura - Commutative AlgebraFor specialists in commutative algebra, this book will serve as an introduction to the more difficult and detailed books of Nagata and Grothendieck. To ...
-
[32]
[PDF] 23 Hom and ⊗ - BrandeisWe would like to say that tensor product (A ⊗R −) and HomR(A,−) are adjoint additive functors R-Mod → R-Mod. However, tensor product is (so far) only defined up ...
-
[33]
[PDF] DUAL MODULES 1. Introduction Let R be a commutative ring. For ...For R-modules M, N, the bilinear maps M × N → R are denoted. BilR(M,N;R). Under the usual addition and scaling of bilinear maps, BilR(M,N;R) is an R-module.
-
[34]
[PDF] Introduction to representation theory - MIT MathematicsJan 10, 2011 · Find the characters and tensor products of irreducible complex representations of the Heisenberg group from Problem 3.18. Problem 3.26. Let ...
-
[35]
tensor product of chain complexes in nLabSep 7, 2023 · The tensor product of chain complexes is a natural tensor product that makes the category of chain complexes into a closed monoidal category. ...Definition · Properties · Examples
-
[36]
[PDF] MATH 60440 Tensor product of chain complexes Spring 2014 ...The tensor product of chain complexes (A∗ ⊗R B∗)n is defined as ⊕ Ai ⊗R Bj, where the boundary map is ∂A⊗B = ⊕ ∂A i ⊗ 1Bj + (−1)i1Ai ⊗ ∂B j.
-
[37]
Section 15.62 (061Y): Spectral sequences for Tor—The Stacks projectIn this section we collect various spectral sequences that come up when considering the Tor functors.
-
[38]
"Flat chain complex"? - abstract algebra - Math Stack ExchangeJan 18, 2021 · Given a flat module F and an exact sequence A∙, a tensor product of chain complexes F⊗A∙. is again exact, where ⊗ is defined as in Tensor ...Condition for the tensor product functor (−)⊗B of chain complexes ...Tensor product of exact complexes is exact - Math Stack ExchangeMore results from math.stackexchange.com
-
[39]
[PDF] Algebraic Topology I: Lecture 25 Künneth and Eilenberg-ZilberDefinition 25.1. Let C∗,D∗ be two chain complexes. Their tensor product is the chain complex with. (C∗ ⊗ D∗)n = M p+q=n. Cp ⊗ Dq . The differential (C ...<|control11|><|separator|>
- [40]
-
[41]
Section 21.46 (08FY): Tor dimension—The Stacks project21.46 Tor dimension. In this section we take a closer look at resolutions by flat modules. Definition 21.46.1. Let (\mathcal{C}, \mathcal{O}) be a ringed ...
-
[42]
43.14 Intersection multiplicities using Tor formula - Stacks Project43.14 Intersection multiplicities using Tor formula. A basic fact we will use frequently is that given sheaves of modules \mathcal{F}, \mathcal{G} on a ...
-
[43]
Lemma 17.16.6 (01CE)—The Stacks project### Summary of Lemmas on Coherence and Flatness from Tag 01CE
- [44]
-
[45]
Lemma 26.7.2 (01I8)—The Stacks project... tensor product of sheaves of modules. To see that this map is an isomorphism it suffices to check that it is an isomorphism on stalks. And this follows from ...
-
[46]
Section 17.25 (01CR): Invertible modules—The Stacks projectAn invertible module is a sheaf of modules where tensoring with it creates an equivalence of categories, or where there exists a module N such that L tensor N ...