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References
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10.39 Flat modules and flat ring maps - Stacks ProjectAn R-module M is called flat if whenever N_1 \to N_2 \to N_3 is an exact sequence of R-modules the sequence M \otimes _ R N_1 \to M \otimes _ R N_2 \to M \ ...
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flat module in nLabMay 12, 2025 · An R R -module M M is flat (from the French word “plat”) if it has “no torsion” in the sense that the Tor-functor vanishes for every R R -module ...
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[PDF] Some module theory - Purdue Math(b) Projective modules are flat. (c) If R is a (commutative) PID, a module is flat if and only if it is torsion free. Proof. Suppose that M ! N is injective ...
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Flat modules - Konrad Voelkel «Oct 30, 2010 · Flat modules are the "local" model for flat morphisms of schemes. Flatness is an essential part of the definition of étale morphisms.
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[PDF] Homological AlgebraWe shall give an account of this theory in Ch. xm; however we do not enterinto its main applications to semi-simple Lie algebras and compact Lie groups.
- [7]
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[PDF] Hideyuki Matsumura - Commutative AlgebraPart I is a self-contained exposition of basis concepts such as flatness, dimen- sion, depth, normal rings, and regular local rings. Part II deals with the ...
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Section 15.22 (0549): Torsion free modules—The Stacks projectAny flat R-module is torsion free. Proof. If x \in R is nonzero, then x : R \to R is injective, and hence if M is flat over R, then x : M \to M is injective.
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WHEN FLATS ARE TORSION FREE - Cambridge University PressWHEN FLATS ARE TORSION FREE. 561. COROLLARY. Let R be a commutative integral domain. Then flat is equivalent to torsion free if and only if vt.gl.dim R<\.
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Flat module and torsion-free module - MathOverflowJan 4, 2011 · Is there a general condition under which a torsion free module over R is flat? What is the simplest example of torsion-free non-flat module over ...How to introduce notions of flat, projective and free modules?A finitely generated, locally free module over a domain which is not ...More results from mathoverflow.net
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Section 41.9 (0250): Flat morphisms—The Stacks projectFree and projective modules are flat. This is clear for free modules and follows for projective modules as they are direct summands of free modules and ...
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Section 10.77 (05CD): Projective modules—The Stacks projectA direct sum of projective modules is projective. Proof. This is true ... Since both P and M are flat R-modules we can identify this with the map. I^ a ...
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Section 10.78 (00NV): Finite projective modules—The Stacks projectIt is not true that a finite R-module which is R-flat is automatically projective. A counter example is where R = \mathcal{C}^\infty (\mathbf{R}) is the ...
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[PDF] Graduate Algebra, Fall 2014 Lecture 41Dec 10, 2014 · Theorem 3. Let R be an integral domain and M an R-module. 1. If M is flat over R then M is torsion-free, i.e., AnnR(M)=0.
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[PDF] Lecture 22 - OSU Mathtorsion-free module if Nor = 0. ‡ (o), we. If Ntor + (0) say. "N has torsion". Lemma. (R: intégral domain). N has torsion ⇒ N is not flat- pf. Let aER be such ...
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[PDF] Week 6: Flatness and Tor - Purdue Mathis clear by considering E as a quotient of a free module H. Finally, to ... A submodule of a flat module need not be flat. Take for example. A = k[X,Y ] ...
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Proposition 10.90.6 (05CZ)—The Stacks projectLet R be a ring. The following are equivalent. R is coherent,. any product of flat R-modules is flat, and. for every set A the module R^ A is flat. Proof ...
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Direct Sum/Product of Flat Modules - Mathematics Stack ExchangeMar 11, 2013 · Flat right R-modules are closed under infinite products. An inspection of the proof shows more precisely: Let R be a ring which is not left ...Prove that M is flat ⟺ each Mi is flat (2.4 Atiyah & MacDonald pg. 31)Faithfully flat direct sum - abstract algebra - Math Stack ExchangeMore results from math.stackexchange.com
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[PDF] Flat modules in algebraic geometry - NumdamDEFINITION 1: The pure transform M0394 of M, by the blowing up. S' ~ S, is the coherent sheaf M'/N'. So the pure transform M039B is characterized by the ...
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Lemma 15.27.4 (0912)—The Stacks projectLemma 15.27.4. Let A be a Noetherian ring. Let I be an ideal of A. Let (M_ n) be an inverse system of A-modules such that. M_ n is a flat A/I^ n-module,.
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[PDF] Contents - UChicago MathA finitely presented flat module over a local ring is in fact free, but we do not prove this (except when the ring is noetherian, see ??). Proof. Indeed, let R ...
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None### Summary of Theorem Characterizing Flat Modules Using Tor_1(R/I, M)=0
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Section 15.59 (06XY): Derived tensor product—The Stacks projectIn fact, it turns out that the boundedness assumptions are not necessary, provided we choose K-flat resolutions. Definition 15.59.1. Let R be a ring. A complex ...<|control11|><|separator|>
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[PDF] Homological Algebra - Purdue Mathflat, projective, injective). (Flat modules are defined in Definition 2.3, projective modules in. Section 5 and injective modules in Section 24.) An exact ...
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Section 10.75 (00LY): Tor groups and flatness—The Stacks project10.75 Tor groups and flatness. In this section we use some of the homological algebra developed in the previous section to explain what Tor groups are.Missing: characterization | Show results with:characterization
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Can a quotient ring R/J ever be flat over R? - MathOverflowOct 8, 2009 · You have to be careful. If you put that A-module structure on A, it is not flat. In your construction, the quotient you consider is A/(x_1), ...
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Example for $R[X]/(rX)$ is a flat $R$-module - Math Stack ExchangeNov 7, 2017 · Then R[X]/(rX) is not flat as an R algebra if R is an integral domain. But what can we say if R is not an integral domain ? EDIT: Consider a ...Prove that the polynomial ring $R[x]$ is a flat $R$-module.ring theory - Can it be that $R[[x]]$ is flat over $R$ but not over $R[x]$?More results from math.stackexchange.com
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[PDF] Introduction to Commutative Algebra - OSU MathApr 8, 2008 · of an A-module homomorphism is a local property. 8. Page 15. Chapter 1 ... Since A[x] is a free A-module, A[x] is a flat A module.
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Section 29.25 (01U2): Flat morphisms—The Stacks project29.25 Flat morphisms. Flatness is one of the most important technical tools in algebraic geometry. In this section we introduce this notion.
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Lemma 10.39.17 (00HR)—The Stacks projectThe Stacks project · bibliography · blog · Table of contents; Part 1 ... Lemma 10.39.17. A flat local ring homomorphism of local rings is faithfully ...
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Lemma 10.39.16 (00HQ)—The Stacks project### Summary of Lemma 10.39.16 (00HQ) from The Stacks Project
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Lemma 10.97.3 (00MC)—The Stacks projectIn particular, if (R, \mathfrak m) is a Noetherian local ring, then the completion \mathop{\mathrm{lim}}\nolimits _ n R/\mathfrak m^ n is faithfully flat.
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Section 10.164 (033D): Descending properties—The Stacks projectIn this section we start proving some algebraic facts concerning the “descent” of properties of rings. It turns out that it is often “easier” to descend ...
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15.45 Permanence of properties under henselization - Stacks ProjectThe Stacks project · bibliography · blog · Table of contents; Part 1 ... As a flat local ring homomorphism is faithfully flat (Algebra, Lemma 10.39.17) ...
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Commutative algebra: Constructive methods.Finite projective modulesThis book is an introductory course to basic commutative algebra with a par- ticular emphasis on finitely generated projective modules, ...