Escape velocity
Escape velocity, also known as escape speed, is the minimum speed that an unbound spacecraft or other object must reach to escape the gravitational influence of a celestial body, such as a planet or moon, without any further propulsion.[1] This velocity is derived from the principle of conservation of mechanical energy, where the initial kinetic energy of the object at the surface equals the absolute value of its gravitational potential energy, ensuring that at infinite distance, the total energy is zero and the object does not fall back.[1] The formula for escape velocity from a spherical body is given by v_{\text{esc}} = \sqrt{\frac{2[G](/page/Gravitational_constant)M}{r}}, where [G](/page/Gravitational_constant) is the gravitational constant, M is the mass of the celestial body, and r is the distance from its center (typically the radius for surface launches).[2] For Earth, the escape velocity from the surface is approximately 11.2 kilometers per second (about 25,000 miles per hour), calculated using Earth's mass of $5.97 \times 10^{24} kilograms and mean radius of 6,378 kilometers.[2] This value decreases with altitude, as the effective r increases; for example, at the summit of Mount Everest, it is slightly lower at 11.18 km/s, and at geostationary orbit altitude (about 35,786 km above the surface), it drops to around 4.35 km/s.[3] Escape velocity plays a critical role in space exploration, determining the energy requirements for interplanetary missions—rockets achieving this speed can leave Earth's orbit entirely, while those below it remain bound unless additional thrust is applied.[3] The concept applies universally to any gravitational system, with lower escape velocities for smaller bodies like the Moon (about 2.38 km/s) due to their reduced mass and size, enabling easier launches from such surfaces.[4] In practice, atmospheric drag and other factors like launch trajectory must be considered, but the idealized formula provides the foundational benchmark for ballistic escape.[2]Fundamentals
Definition
Escape velocity is the minimum speed required for an object to escape from the gravitational influence of a celestial body, such as a planet or star, without any additional propulsion, assuming the absence of dissipative forces like atmospheric drag. This velocity ensures that the object's kinetic energy is sufficient to overcome the gravitational potential energy binding it to the body, allowing it to travel indefinitely far away.[5] The escape velocity v_e from a point at distance r from the center of a body of mass M is given by the formula v_e = \sqrt{\frac{2GM}{r}}, where G is the gravitational constant ($6.67430 \times 10^{-11} \, \mathrm{m^3 \, kg^{-1} \, s^{-2}}). This expression arises from equating the initial kinetic energy to the absolute value of the gravitational potential energy at that distance.[5][6] When launched at exactly the escape velocity, the object follows a parabolic trajectory and reaches infinite distance from the central body with zero remaining kinetic energy, having converted all its initial kinetic energy into gravitational potential energy. Escape velocity is typically measured in meters per second (m/s) or kilometers per second (km/s); for example, from Earth's surface, it is approximately 11.2 km/s.[5][7]Physical Significance
The concept of escape velocity was first conceptualized by Isaac Newton in his Philosophiæ Naturalis Principia Mathematica (1687), through a thought experiment depicting a cannon fired horizontally from a tall mountain, where increasing the projectile's speed transitions from falling back to Earth, to circular orbit, and finally to escaping the planet's gravitational attraction entirely.[8] This idea laid foundational groundwork in orbital mechanics, with the formal application of the concept emerging in 18th- and 19th-century astrophysics, particularly through the works of John Michell and Pierre-Simon Laplace, who extended the principle to stellar phenomena.[9] In gravitational dynamics, escape velocity serves as the critical threshold distinguishing bound from unbound orbits: trajectories with speeds below this value result in closed, elliptical paths where the object remains gravitationally captured, whereas speeds at or above it produce parabolic or hyperbolic paths, allowing the object to depart indefinitely without returning.[10] This demarcation is essential for understanding celestial mechanics, as it delineates stable systems like planetary orbits from transient encounters, such as comets originating from distant regions of the solar system. Escape velocity also plays a pivotal role in planetary science by determining the retention of atmospheres over geological timescales; planets with sufficiently high escape velocities can gravitationally bind lighter gases against thermal motion, preventing their diffusion into space, while those with low values lose volatiles readily.[11] For instance, Mercury's minimal escape velocity, combined with its proximity to the Sun and high surface temperatures, enables atmospheric gases to achieve speeds exceeding this threshold, resulting in the planet's near-total lack of a stable atmosphere.[12] Conceptually, escape velocity provides an intuitive Newtonian analogy for extreme gravitational phenomena, such as black holes, where the event horizon represents a boundary beyond which the required escape speed equals or exceeds the speed of light, rendering escape impossible even for photons—a limit first explored by Michell in 1783 when he posited stars massive enough for light's escape velocity to surpass its propagation speed.[9]Derivation
Newtonian Approach
In the Newtonian approach, escape velocity is derived by first considering the balance of forces for a circular orbit and then extending this to the limiting case of a parabolic trajectory, where the object just escapes to infinity without further propulsion. This method relies on classical mechanics, treating gravity as the central force providing the necessary centripetal acceleration for orbital motion.[13] Consider an object of mass m orbiting a central body of mass M at a distance r from its center. For a circular orbit, the gravitational force acts as the centripetal force required to maintain the curved path. Newton's law of universal gravitation gives the attractive force as F_g = \frac{G M m}{r^2}, where G is the gravitational constant.[13] The centripetal force needed is F_c = \frac{m v^2}{r}, where v is the orbital speed.[13] Equating these forces yields: \frac{G M m}{r^2} = \frac{m v^2}{r}. Canceling m and multiplying both sides by r simplifies to: \frac{G M}{r} = v^2, so the circular orbital speed is: v = \sqrt{\frac{G M}{r}}. [13] To find the escape velocity, consider the condition where the trajectory becomes parabolic, allowing the object to reach infinite distance with zero speed at infinity. In Newtonian mechanics, this initial speed at radius r is \sqrt{2} times the circular orbital speed at the same radius, giving: v_{\text{esc}} = \sqrt{\frac{2 G M}{r}}. [14] This derivation assumes the central body can be treated as a point mass (valid for spherically symmetric distributions by the shell theorem), neglects relativistic effects, and considers motion in a vacuum without dissipative forces.[13][14] It ignores energy losses from atmospheric drag or other resistances, which are negligible in idealized space conditions but significant near planetary surfaces.[14] The approach is valid only for speeds much less than the speed of light (v \ll c), where special relativity does not alter the dynamics.[15]Energy Conservation Method
The energy conservation method derives the escape velocity by considering the total mechanical energy of a particle in a gravitational field, which remains constant in the absence of non-conservative forces. The total energy E of a particle of mass m at a distance r from the center of a much larger mass M is given by the sum of its kinetic energy and gravitational potential energy: E = \frac{1}{2} m v^2 - \frac{G M m}{r}, where v is the speed at r and G is the gravitational constant.[1] The gravitational potential energy U arises from the work done against the gravitational force F_g = \frac{G M m}{r^2}, which points radially inward. The potential energy is defined such that F_g = -\frac{dU}{dr}, leading to U(r) = -\int_{\infty}^{r} F_g \, dr' = -\frac{G M m}{r}. This choice sets U = 0 at infinite separation (r \to \infty), where the gravitational influence vanishes, and makes U negative and approaching -\infty as r \to 0, reflecting the binding nature of gravity.[16] For a particle to escape to infinity from radius r, its total energy must be non-negative (E \geq 0) so it can reach r \to \infty without additional propulsion. At infinity, the potential energy is zero, and the minimum condition corresponds to zero kinetic energy there (just barely escaping). Thus, setting E = 0 at the launch point gives \frac{1}{2} m v_e^2 - \frac{G M m}{r} = 0, yielding the escape velocity v_e = \sqrt{\frac{2 G M}{r}}. This is the minimum initial speed required for escape.[1] In comparison to circular orbital motion at the same radius, the orbital speed v_o = \sqrt{\frac{G M}{r}} requires kinetic energy \frac{1}{2} m v_o^2 = \frac{G M m}{2 r}, while escape demands twice that amount (\frac{1}{2} m v_e^2 = \frac{G M m}{r}), or equivalently v_e = \sqrt{2} \, v_o, highlighting the additional energy needed to unbind the particle entirely rather than sustain a bound orbit.Advanced Considerations
Relativistic Escape Velocity
In special relativity, the escape velocity is adjusted by equating the relativistic kinetic energy to the absolute value of the Newtonian gravitational potential energy. The relativistic kinetic energy is (\gamma - 1) m c^2, where \gamma = \frac{1}{\sqrt{1 - v^2/c^2}}, set equal to \frac{G M m}{r}. Solving for v, the formula becomes v_e = c \sqrt{1 - \left(1 + \frac{GM}{r c^2}\right)^{-2}} This expression reduces to the Newtonian limit v_e = \sqrt{\frac{2 G M}{r}} for weak fields (small \frac{G M}{r c^2}) but approaches the speed of light c as the gravitational field strengthens, preventing superluminal speeds.[17] In general relativity, the Schwarzschild metric describes the spacetime around a spherically symmetric, non-rotating mass, providing the framework for escape velocity from radius r. The escape velocity is derived from the geodesic equations, yielding a form that approaches c at the event horizon, where the Schwarzschild radius r_s = 2GM/c^2 defines the boundary beyond which escape is impossible. At r = r_s, the escape velocity equals c, as light itself cannot escape.[18] The relativistic formulation differs from the Newtonian approach due to gravitational time dilation and spacetime curvature, which alter the effective energy requirements and trajectories. Near compact objects, time dilation slows clocks relative to distant observers, increasing the energy needed for escape, while curvature bends paths, making unbound orbits more demanding than in flat space.[19] These concepts apply to compact stellar remnants, such as neutron stars, where surface escape velocities range from 0.4c to 0.6c due to their high mass (approximately 1.4 solar masses) and small radius (about 10-15 km), requiring relativistic corrections for accurate modeling of particle ejection or accretion. White dwarfs, with lower compactness, have escape velocities around 0.01c to 0.02c (e.g., 5500 km/s for a solar-mass white dwarf of radius 8800 km), where relativistic effects are minimal but still influence surface dynamics in binary systems.[20][21]Calculus-Based Derivation
To derive the escape velocity using calculus, consider a particle of mass m launched from a distance r from the center of a spherically symmetric mass M, such as a planet, under the influence of Newtonian gravity. The gravitational acceleration toward the center is given by Newton's law of universal gravitation, a = -\frac{GM}{r^2}, where G is the gravitational constant and the negative sign indicates attraction.[22] For motion along a path, the acceleration can be expressed in terms of velocity v and radial distance using the chain rule: \frac{dv}{dt} = v \frac{dv}{dr} = -\frac{GM}{r^2}. This differential equation relates the change in speed to the change in distance, assuming no other forces like drag.[23] To find the initial speed v_e required for the particle to reach infinity with zero velocity, integrate the differential equation. Separate variables to obtain v \, dv = -\frac{GM}{r^2} \, dr, then integrate from the initial speed v_e at distance r to final speed 0 at r \to \infty: \int_{v_e}^{0} v \, dv = -GM \int_{r}^{\infty} \frac{1}{r^2} \, dr. The left side evaluates to \left[ \frac{1}{2} v^2 \right]_{v_e}^{0} = -\frac{1}{2} v_e^2, while the right side is -GM \left[ -\frac{1}{r} \right]_{r}^{\infty} = -\frac{GM}{r}. Thus, -\frac{1}{2} v_e^2 = -\frac{GM}{r}, so \frac{1}{2} v_e^2 = \frac{GM}{r}, leading to v_e = \sqrt{\frac{2GM}{r}}. This result holds under the assumption of spherical symmetry, where the gravitational field behaves as if all mass is concentrated at the center for points outside the body.[22][24] The derivation demonstrates path independence: the required escape speed v_e is the same regardless of launch direction (radial outward or at an angle), as the integration captures the cumulative effect of the conservative gravitational force along any path to infinity, without dependence on the specific trajectory.[23] This calculus-based approach is equivalent to the energy conservation method, where the initial kinetic energy equals the absolute value of the gravitational potential energy difference to infinity.[24] For generalizations, the derivation extends to cases with varying central mass M(r) or non-point sources, provided the gravitational field follows Gauss's law for spherical symmetry, g(r) = -\frac{GM(r)}{r^2}, where M(r) is the enclosed mass within radius r; however, the focus remains on uniform spherical bodies where M is constant.[22]Application Scenarios
Surface Launch from Non-Rotating Bodies
For launches from the surface of a non-rotating celestial body, such as a planet or moon, the escape velocity represents the minimum speed required for an object to depart without further propulsion, overcoming the body's gravitational pull under Newtonian mechanics. This scenario assumes a direct radial launch from the surface, neglecting any rotational motion of the body or atmospheric influences for an idealized calculation. The governing formula is derived from the conservation of mechanical energy, where the initial kinetic energy of the launched object must equal the gravitational potential energy needed to reach infinity. Specifically, the escape velocity v_e at the surface is given by v_e = \sqrt{\frac{2GM}{R}}, where G is the gravitational constant, M is the mass of the body, and R is its radius. This expression quantifies how the escape speed scales with the body's mass and inversely with the square root of its radius, emphasizing that more massive or compact bodies demand higher velocities for escape.[3] A useful reformulation relates escape velocity directly to the surface gravity g of the body, defined as g = \frac{GM}{R^2}. Substituting this into the formula yields v_e = \sqrt{2gR}, which highlights the interplay between local gravitational acceleration and the body's size. For instance, bodies with strong surface gravity but large radii, like gas giants, exhibit exceptionally high escape velocities due to the R term amplifying the effect. This relation is particularly insightful for mission planning, as it allows engineers to estimate requirements using measurable surface parameters rather than requiring precise knowledge of the body's total mass.[25] Applying this to specific solar system bodies illustrates the range of escape velocities. For Earth, with a surface gravity of approximately 9.8 m/s² and radius of about 6371 km, the escape velocity is 11.2 km/s, a benchmark for human spaceflight launches. The Moon, possessing a much weaker surface gravity of 1.62 m/s² and radius of 1737 km, has an escape velocity of 2.38 km/s, facilitating easier departures as demonstrated by Apollo missions. In contrast, Jupiter's immense mass and radius result in an escape velocity of 59.5 km/s at its 1-bar cloud level, underscoring the challenges of escaping gas giants despite their diffuse structure. These values assume vacuum conditions at the surface; in reality, atmospheric drag on bodies like Earth can reduce the effective velocity by about 0.1 to 0.3 km/s through energy dissipation during ascent, though such effects are excluded from this idealized non-rotating model.[25][26][27][28]Effects of Rotation and Orbit
Planetary rotation imparts an initial tangential velocity to objects launched from the surface, which can reduce the required relative launch speed to achieve escape conditions. For an equatorial launch in the prograde direction, this rotational boost effectively lowers the escape velocity to \sqrt{v_e^2 - v_{\rm rot}^2}, where v_e is the standard escape velocity from the non-rotating body and v_{\rm rot} is the equatorial tangential speed due to rotation. This formula arises from the vector addition of velocities, assuming the launch direction is such that the rotational component contributes perpendicularly to the primary thrust vector in the energy calculation. On Earth, v_{\rm rot} \approx 0.46 km/s at the equator, resulting in a minor reduction from the baseline v_e = 11.2 km/s to approximately 11.19 km/s, highlighting the limited but measurable benefit for low-mass planets like Earth.[29] The direction of launch significantly influences the magnitude of this boost. Prograde launches, aligned with the planet's rotation, maximize the gain by adding the rotational velocity vectorially to the launch velocity, whereas retrograde or polar launches provide no such advantage or even require additional compensation. This directional dependence is particularly relevant for optimizing fuel efficiency in real missions, where equatorial sites like Kennedy Space Center (at 28.5° latitude) still capture a portion of the boost through \cos(\lambda), with \lambda the latitude. For faster-rotating bodies like Jupiter, where v_{\rm rot} \approx 12.6 km/s at the equator exceeds the escape velocity of 59.5 km/s in some contexts, the effect becomes more substantial, though atmospheric and oblateness complications arise.[29] Launching from an established orbit further modifies the escape requirements, as the orbital velocity already provides a substantial initial speed relative to the central body. The effective escape speed from orbit is given by v_{\rm esc,orb} = \sqrt{v_e^2 - v_{\rm orb}^2}, where v_e = \sqrt{2GM/r} is the local escape velocity at orbital radius r and v_{\rm orb} = \sqrt{GM/r} for a circular orbit; this simplifies to v_{\rm orb}. In low Earth orbit (LEO) at approximately 200 km altitude, v_{\rm orb} \approx 7.8 km/s, yielding a total inertial speed of about 10.8-11.0 km/s needed for escape, but the delta-v imparted by the spacecraft is lower—typically around 3.2 km/s for an optimal tangential prograde burn to reach hyperbolic trajectory with zero excess hyperbolic speed. Prograde burns in the direction of orbital motion maximize this efficiency, similar to surface rotation effects.[28] These calculations rely on the two-body approximation, treating the launch or orbital escape as motion dominated by the primary body's gravity, which remains valid when the spacecraft's trajectory is well within the body's Hill sphere and distant from significant perturbations by other bodies like the Sun or companion planets. This simplification holds for most practical interplanetary launches from Earth or other solar system bodies, where third-body effects become negligible beyond low orbits.[30]Barycentric and Practical Limits
In multi-body gravitational systems, such as the Earth-Sun setup, the escape velocity is defined relative to the system's barycenter, which approximates the Sun's position for solar system dynamics. For a spacecraft in Earth orbit to escape the solar system, it must achieve a heliocentric speed of approximately 42 km/s at 1 AU, directed away from the Sun, exceeding the Earth's orbital velocity of about 30 km/s. This barycentric requirement ensures the object transitions from bound to unbound relative to the central mass, preventing recapture by the system's dominant gravitational influence. The Hill sphere delineates the volume around a secondary body, like a planet, where its gravitational pull prevails over the primary body's (e.g., the Sun's) perturbations, defining the practical boundary for stable satellites or temporary escape. Its radius is approximated by the formula r_H \approx a \left( \frac{m}{3M} \right)^{1/3}, where a is the secondary's semi-major axis around the primary, m is the secondary's mass, and M is the primary's mass. Exceeding this sphere without sufficient velocity relative to the barycenter typically results in the object being drawn into a heliocentric orbit or captured by the primary, as the secondary's influence wanes beyond r_H. Real-world engineering constraints impose additional limits beyond ideal two-body calculations. Atmospheric drag during launch from bodies with significant atmospheres, such as Earth, dissipates kinetic energy, necessitating higher initial thrust and velocities—up to several percent above theoretical escape speed—to compensate for losses in the dense lower layers. Multi-stage rocket designs mitigate mass penalties by sequentially discarding empty propellant tanks, optimizing the thrust-to-weight ratio to accumulate the required delta-v for escape while minimizing overall fuel mass. The Oberth effect further influences practical trajectories, amplifying energy gain from propulsion when applied at higher velocities, such as near periapsis in an elliptical orbit, making low-altitude burns more efficient for achieving escape despite not minimizing instantaneous velocity. Consequently, the minimum-energy path to escape often involves higher speeds at key points rather than a direct minimum-velocity ascent, balancing fuel efficiency with gravitational losses. For low-thrust propulsion systems, gradual acceleration enables escape without attaining the full instantaneous escape velocity at any single point. Continuous or intermittent thrusting allows the spacecraft to spiral outward, incrementally increasing orbital energy until unbound, as demonstrated in optimal low-thrust escape analyses where the trajectory avoids the impulsive delta-v demands of classical escape.Trajectories and Extensions
Escape Trajectory Shapes
When an object is launched from a central gravitational body at a speed equal to or greater than the escape velocity, it follows an unbound trajectory that extends to infinity. For non-zero angular momentum, this path is a hyperbola with eccentricity e > 1, characterized by two asymptotes that the trajectory approaches as the distance from the central body increases without bound. The eccentricity is given by e = \sqrt{1 + \frac{2 E L^2}{G^2 M^2 m^3}}, where E is the total mechanical energy of the object, L is its angular momentum, G is the gravitational constant, M is the mass of the central body, and m is the mass of the object.[31] This hyperbolic shape arises because the positive total energy ensures the object cannot be captured, with the branches of the hyperbola representing the incoming and outgoing paths relative to the focus at the central body.[32] Key parameters of the hyperbolic trajectory include the semi-major axis a, which becomes infinite for the exact escape case where the total energy E = 0, corresponding to zero hyperbolic excess velocity.[31] Any excess speed above escape velocity results in a finite (negative in convention) semi-major axis and determines the angle of the asymptotes; specifically, the true anomaly at which the asymptotes are approached satisfies \cos \delta = -1/e, where \delta is the semi-angle between the periapsis and each asymptote, with smaller excess speeds yielding larger \delta and a wider opening angle.[31] In the special case of radial escape, where the launch direction is directly away from the central body and angular momentum L = 0, the trajectory degenerates to a straight line along the radial direction.[32] This simplest unbound path requires only that the initial speed meets or exceeds the local escape velocity, with no transverse motion to curve the orbit. For visualization, the parabolic trajectory with e = 1 represents the limiting case of exact escape, where the object reaches infinity with zero velocity; any additional kinetic energy produces a hyperbolic path with e > 1, opening the trajectory into distinct asymptotes that diverge more sharply as excess speed increases.[31]Altitudes for Sub-Escape Speeds
When a projectile is launched vertically from the surface of a celestial body with an initial speed v < v_e, where v_e = \sqrt{2GM/r_p} is the escape speed at perigee distance r_p (typically the body's radius R), the total mechanical energy E is negative, resulting in a bound trajectory. The maximum altitude, or apoapsis distance r_a, occurs where the kinetic energy is zero, and energy conservation yields the relation \frac{1}{2} m v^2 - \frac{GMm}{r_p} = -\frac{GMm}{r_a}. Solving for r_a gives r_a = \frac{GM}{\frac{GM}{r_p} - \frac{1}{2} v^2}, or equivalently, the height above the surface h = r_a - r_p = \frac{r_p v^2}{2GM/r_p - v^2}, assuming v^2 < 2GM/r_p to ensure E < 0. This formula accounts for the inverse-square gravitational potential and contrasts with low-altitude approximations like h \approx v^2 / (2g), where g = GM/r_p^2, which underestimate heights for high-speed launches.[33] As the launch speed v approaches v_e from below, the denominator \frac{GM}{r_p} - \frac{1}{2} v^2 approaches zero from the positive side, causing r_a \to \infty. In this limit, the trajectory becomes a highly eccentric ellipse, and the time to reach apoapsis also diverges to infinity, reflecting the increasingly gentle gravitational pull at large distances. For non-radial launches forming proper elliptical orbits, the apoapsis follows from the vis-viva equation and angular momentum conservation, but the energy condition E < 0 similarly bounds the maximum radius.[33] Practical examples illustrate these sub-escape limits. Ballistic missiles, such as the Soviet-era Scud with a range of 300 km, achieve maximum altitudes around 150 km when fired vertically, far short of escape due to their burnout speeds of approximately 1–2 km/s compared to Earth's v_e \approx 11.2 km/s. Intercontinental ballistic missiles (ICBMs) reach higher apogees of 1,000–1,500 km during midcourse flight, enabling global ranges but still resulting in reentry rather than escape. These arcs highlight how sub-escape speeds confine trajectories to finite heights, unlike full escape which permits unbounded paths. In environments with significant tidal forces, such as near a planet with close-in moons, sub-escape trajectories approaching the Roche limit—typically 2.44 times the primary's radius for fluid bodies—may experience perturbations that alter the path or disrupt loosely bound payloads. The Roche limit arises from the balance between a body's self-gravity and tidal shear, and for apoapsis near this zone, the effective potential modifies the simple energy-derived height. A slight increase in launch speed beyond v_e shifts E > 0, converting the elliptical trajectory to a hyperbolic one with positive energy allowing escape to infinity at a residual speed v_\infty = \sqrt{v^2 - v_e^2}. This transition underscores the critical role of energy in determining whether a path remains bound or unbound.[33]Comparative Data
Escape Velocities of Solar System Bodies
The escape velocities of Solar System bodies are determined from their surfaces for planets and moons, using the standard method for non-rotating bodies, while for the Sun, the surface value is much higher than the effective escape speed at 1 AU (approximately 42 km/s). These values reflect the gravitational pull needed to overcome the body's attraction, with data sourced from NASA and JPL measurements accurate as of recent planetary parameters.[34][35][36] The following table summarizes key parameters for the Sun, planets, and Earth's Moon, including equatorial radius, mass, and surface escape velocity.| Body | Radius (km) | Mass (10^{24} kg) | Escape Velocity (km/s) |
|---|---|---|---|
| Sun | 695,700 | 1,988,500 | 617.7 |
| Mercury | 2,440 | 0.330 | 4.25 |
| Venus | 6,052 | 4.87 | 10.4 |
| Earth | 6,378 | 5.97 | 11.2 |
| Moon | 1,738 | 0.0735 | 2.38 |
| Mars | 3,396 | 0.642 | 5.03 |
| Jupiter | 71,492 | 1,898 | 60.2 |
| Saturn | 60,268 | 568 | 36.1 |
| Uranus | 25,559 | 86.8 | 21.4 |
| Neptune | 24,764 | 102 | 23.6 |