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Reduced mass

In physics, the reduced mass is an effective mass parameter used to simplify the analysis of two-body systems interacting via a central force, defined for two particles of masses m_1 and m_2 as \mu = \frac{m_1 m_2}{m_1 + m_2}.^[1]^[2] This quantity is equal to half the harmonic mean of the individual masses and arises naturally when transforming the equations of motion for the two-body problem into an equivalent one-body problem, where the reduced mass \mu moves relative to the system's center of mass under the interaction potential.^[3]^[4] The concept originates from classical mechanics, particularly in solving central force problems like gravitational orbits, where the relative motion of the two bodies can be described as if a single particle of mass \mu orbits a fixed point at the center of mass, with the force law unchanged.^[1]^[5] This reduction preserves the conservation laws of momentum and energy while decoupling the center-of-mass motion (which proceeds uniformly) from the internal dynamics.^[2] In the limit where one mass dominates (e.g., m_1 \gg m_2), \mu approximates the lighter mass m_2, justifying approximations like treating the Sun as fixed in planetary motion.^[6]^[7] In quantum mechanics, the reduced mass plays a crucial role in bound-state problems, such as the hydrogen atom, where it replaces the electron mass in the Schrödinger equation to account for the finite nuclear mass, leading to a small but measurable correction to energy levels (on the order of m_e / m_p \approx 1/1836 for hydrogen).^[8]^[9] This adjustment shifts the Rydberg constant and spectral lines, enabling precise tests of quantum theory and nuclear mass ratios via isotope comparisons (e.g., hydrogen vs. deuterium).^[10]^[11] Beyond atoms, reduced mass is essential in molecular spectroscopy for diatomic vibrations and rotations, as well as in scattering theory and effective field theories for composite particles.^[12]^[13]

Definition and Formula

Concept

The reduced mass is a fictitious effective mass that encapsulates the dynamics of relative motion between two interacting bodies in a two-body system, allowing the complicated coupled equations of motion for both bodies to be recast as an equivalent one-body problem.^[2] This concept simplifies the analysis of systems where two particles exert mutual forces on each other, such as in gravitational or electromagnetic interactions, by focusing solely on their separation vector rather than individual trajectories.^[2] By introducing the reduced mass, physicists can treat the relative motion as if one body is stationary at the system's center while the other orbits it, capturing the essential physics without solving for extraneous degrees of freedom.^[14] The idea of reduced mass emerged in the context of 18th-century celestial mechanics, building on Isaac Newton's analysis of mutual gravitational attraction in his Philosophiæ Naturalis Principia Mathematica (1687), where he demonstrated that the paths of two bodies relative to their center of mass follow the same curves as if one were fixed.^[15] It was further formalized in the late 18th century through Joseph-Louis Lagrange's development of analytical mechanics in Mécanique Analytique (1788), which provided a general framework for handling constrained systems and relative coordinates in rigid body dynamics and orbital problems.^[16] This formalization extended the concept beyond gravity to broader applications in dynamics, emphasizing its role in reducing multi-body problems to simpler equivalents.^[17] Intuitively, the reduced mass acts like the inertia of a single composite particle whose motion around the system's center of mass mimics the coupled oscillations or orbits of the original two bodies, making it easier to predict behaviors such as orbital periods or collision outcomes.^[18] In the center-of-mass frame, where the overall translational motion is uniform, the reduced mass governs this internal relative dynamics exclusively.^[2]

Mathematical Expression

The reduced mass \mu for a two-body system with masses m_1 and m_2 is given by the formula

\mu = \frac{m_1 m_2}{m_1 + m_2},

where m_1 and m_2 denote the inertial masses of the two interacting bodies.^[19] The subscripts distinguish the masses associated with each distinct body in the system.^[20] In the International System of Units (SI), \mu has the dimension of mass and is expressed in kilograms (kg).^[21] For N-body systems with more than two particles, the reduced mass is typically applied pairwise to two-body subsystems within approximations, while the complete dynamics demand advanced methods beyond a single effective mass.^[22]

Derivations

Newtonian Mechanics

In Newtonian mechanics, the reduced mass arises in the analysis of the two-body problem, where two point particles interact solely through a central force depending on their relative separation. Consider two bodies with masses m_1 and m_2, positions \mathbf{r}_1 and \mathbf{r}_2, and relative position vector \mathbf{r} = \mathbf{r}_1 - \mathbf{r}_2. The force \mathbf{F}(\mathbf{r}) acts on body 1 toward body 2, with the equal and opposite force -\mathbf{F}(\mathbf{r}) on body 2, assuming the interaction is central and obeys Newton's third law.^[2]^[23] The equations of motion for the system are

m_1 \frac{d^2 \mathbf{r}_1}{dt^2} = \mathbf{F}(\mathbf{r}), \quad m_2 \frac{d^2 \mathbf{r}_2}{dt^2} = -\mathbf{F}(\mathbf{r}).

These describe the acceleration of each body due to the mutual interaction.^[2]^[23] To simplify the problem, introduce the center-of-mass coordinate \mathbf{R} = \frac{m_1 \mathbf{r}_1 + m_2 \mathbf{r}_2}{m_1 + m_2} and retain the relative coordinate \mathbf{r}. The positions can then be expressed as

\mathbf{r}_1 = \mathbf{R} + \frac{m_2}{m_1 + m_2} \mathbf{r}, \quad \mathbf{r}_2 = \mathbf{R} - \frac{m_1}{m_1 + m_2} \mathbf{r}.

Differentiating twice with respect to time gives the accelerations:

\frac{d^2 \mathbf{r}_1}{dt^2} = \frac{d^2 \mathbf{R}}{dt^2} + \frac{m_2}{m_1 + m_2} \frac{d^2 \mathbf{r}}{dt^2}, \quad \frac{d^2 \mathbf{r}_2}{dt^2} = \frac{d^2 \mathbf{R}}{dt^2} - \frac{m_1}{m_1 + m_2} \frac{d^2 \mathbf{r}}{dt^2}.

Substituting into the original equations of motion and solving for \frac{d^2 \mathbf{R}}{dt^2} yields \frac{d^2 \mathbf{R}}{dt^2} = 0 for an isolated system with no external forces, implying the center of mass moves with constant velocity.^[2]^[23] For the relative motion, subtract the equations of motion:

\frac{d^2 \mathbf{r}}{dt^2} = \frac{d^2 \mathbf{r}_1}{dt^2} - \frac{d^2 \mathbf{r}_2}{dt^2} = \frac{\mathbf{F}(\mathbf{r})}{m_1} + \frac{\mathbf{F}(\mathbf{r})}{m_2} = \mathbf{F}(\mathbf{r}) \left( \frac{1}{m_1} + \frac{1}{m_2} \right) = \frac{\mathbf{F}(\mathbf{r})}{\mu},

where the reduced mass is \mu = \frac{m_1 m_2}{m_1 + m_2}. This equation describes the relative motion as equivalent to that of a single particle of mass \mu under the force \mathbf{F}(\mathbf{r}), decoupling the center-of-mass motion from the internal dynamics. The derivation assumes no external forces act on the system, ensuring conservation of total momentum.^[2]^[23]

Lagrangian Mechanics

In Lagrangian mechanics, the reduced mass arises through a coordinate transformation that separates the motion of a two-particle system into center-of-mass and relative components. Consider two particles of masses m_1 and m_2 with positions \mathbf{r}_1 and \mathbf{r}_2. The Lagrangian is L = T - V, where the kinetic energy is

T = \frac{1}{2} m_1 |\dot{\mathbf{r}}_1|^2 + \frac{1}{2} m_2 |\dot{\mathbf{r}}_2|^2

and the potential energy V depends solely on the interparticle separation, V = V(|\mathbf{r}_1 - \mathbf{r}_2|).^[24] Introduce the center-of-mass coordinate \mathbf{R} = \frac{m_1 \mathbf{r}_1 + m_2 \mathbf{r}_2}{M}, where M = m_1 + m_2 is the total mass, and the relative coordinate \mathbf{r} = \mathbf{r}_1 - \mathbf{r}_2. The positions can be expressed as \mathbf{r}_1 = \mathbf{R} + \frac{m_2}{M} \mathbf{r} and \mathbf{r}_2 = \mathbf{R} - \frac{m_1}{M} \mathbf{r}. Differentiating yields the velocities, and substituting into the kinetic energy gives

T = \frac{1}{2} M |\dot{\mathbf{R}}|^2 + \frac{1}{2} \mu |\dot{\mathbf{r}}|^2,

where the reduced mass is \mu = \frac{m_1 m_2}{m_1 + m_2}. The potential remains V(|\mathbf{r}|), independent of \mathbf{R}. Thus, the transformed Lagrangian is

L = \frac{1}{2} M |\dot{\mathbf{R}}|^2 + \frac{1}{2} \mu |\dot{\mathbf{r}}|^2 - V(|\mathbf{r}|).

^[24] The Euler-Lagrange equations \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{q}_i} \right) = \frac{\partial L}{\partial q_i} applied to \mathbf{R} yield \frac{d}{dt} (M \dot{\mathbf{R}}) = 0, since \frac{\partial L}{\partial \mathbf{R}} = 0; this conserves the total linear momentum \mathbf{P} = M \dot{\mathbf{R}}, so \dot{\mathbf{R}} is constant. For the relative coordinate \mathbf{r}, the equation simplifies to \mu \ddot{\mathbf{r}} = -\nabla_{\mathbf{r}} V(|\mathbf{r}|), describing the motion of an effective single particle of mass \mu in the potential V.^[24] This approach demonstrates the separability of the system's dynamics: the center-of-mass motion is uniform and decoupled from the internal relative motion, which behaves as an independent central-force problem. Such separation facilitates solving integrable systems by isolating variables and identifying symmetries that lead to conserved quantities.^[24]

Properties

Mathematical Characteristics

The reduced mass \mu for a two-body system with masses m_1 and m_2 is given by the formula

\mu = \frac{m_1 m_2}{m_1 + m_2}.

This expression exhibits symmetry under the interchange of m_1 and m_2, as the formula remains unchanged regardless of which mass is labeled first.^[7] A key algebraic property is that \mu \leq \min(m_1, m_2), with strict inequality unless one mass is infinite; equality holds in the limit as one mass approaches infinity, where \mu approaches the finite mass.^[25] In limiting cases, if m_1 \gg m_2, then \mu \approx m_2, corresponding to the lighter body orbiting a nearly fixed heavier one; conversely, if m_1 = m_2 = m, then \mu = m/2.^[7] The formula admits an equivalent interpretation as the reciprocal of the sum of reciprocals:

\frac{1}{\mu} = \frac{1}{m_1} + \frac{1}{m_2},

which underscores its relation to the harmonic mean (up to a factor of 2 for equal masses).^[7] This form is particularly useful in numerical computations, as it enhances stability when masses are large and nearly equal by avoiding potential overflow in the product m_1 m_2 while precisely handling the summation of small reciprocals.^[25]

Relation to Center-of-Mass Frame

In the two-body problem, the total kinetic energy of the system can be decomposed into the translational kinetic energy of the center of mass and the kinetic energy associated with the relative motion between the two particles. Specifically, for two particles with masses m_1 and m_2, positions \mathbf{r}_1 and \mathbf{r}_2, and velocities \dot{\mathbf{r}}_1 and \dot{\mathbf{r}}_2, the center-of-mass position is \mathbf{R} = \frac{m_1 \mathbf{r}_1 + m_2 \mathbf{r}_2}{M} where M = m_1 + m_2, and the relative position is \mathbf{r} = \mathbf{r}_1 - \mathbf{r}_2. The total kinetic energy T then separates as T = \frac{1}{2} M |\dot{\mathbf{R}}|^2 + \frac{1}{2} \mu |\dot{\mathbf{r}}|^2, where \mu = \frac{m_1 m_2}{M} is the reduced mass.^[26]^[27] This decomposition isolates the uniform motion of the center of mass from the internal dynamics governed by the reduced mass.^[28] In an inertial frame, the full two-body motion involves coupled equations for both particles, but transforming to the center-of-mass frame simplifies the problem significantly. In this frame, the total momentum is zero, so m_1 \dot{\mathbf{r}}_1 + m_2 \dot{\mathbf{r}}_2 = 0, and the velocities become \dot{\mathbf{r}}_1 = \frac{m_2}{M} \dot{\mathbf{r}} and \dot{\mathbf{r}}_2 = -\frac{m_1}{M} \dot{\mathbf{r}}. The relative motion then reduces to an equivalent one-body problem where a particle of mass \mu orbits a fixed center of mass under the interaction potential between the original particles.^[12]^[2] This frame eliminates the translational degrees of freedom, focusing computational and analytical efforts on the relative coordinates.^[29] Conservation laws further highlight the utility of this separation. The center-of-mass position \mathbf{[R](/page/R)} moves with constant velocity in the absence of external forces, conserving total linear momentum \mathbf{[P](/page/P′′)} = M \dot{\mathbf{[R](/page/R)}}. For the relative motion, angular momentum is conserved as \mathbf{[L](/page/L')} = \mu \mathbf{r} \times \dot{\mathbf{r}}, scaled by the reduced mass, which governs the rotational dynamics in the center-of-mass frame.^[30]^[31] This framework is particularly valuable in astrophysical simulations, such as N-body codes modeling stellar clusters or galactic dynamics, where binary interactions are approximated by treating close pairs in their center-of-mass frame using the reduced mass to integrate relative orbits efficiently while advancing the overall center-of-mass motion.^[32]^[33] This reduces computational complexity for multi-body systems by decoupling binary subsystems from the global evolution.^[34]

Classical Applications

Gravitational Two-Body Motion

In the gravitational two-body problem, the motion of two point masses m_1 and m_2 interacting via Newton's law of universal gravitation can be reduced to the equivalent motion of a single body with reduced mass \mu = \frac{m_1 m_2}{m_1 + m_2} orbiting a fixed central mass M = m_1 + m_2. This reduction simplifies the dynamics by separating the problem into center-of-mass motion (uniform translation) and relative motion, where the relative vector \mathbf{r} = \mathbf{r}_1 - \mathbf{r}_2 evolves under an effective central force \mathbf{F} = -\frac{G m_1 m_2}{r^2} \hat{r}. The Lagrangian for the relative motion is then L = \frac{1}{2} \mu \dot{\mathbf{r}}^2 + \frac{G m_1 m_2}{r}, leading to equations of motion identical to those of a test particle in a fixed potential scaled by the total mass.^[2]^[35] For bound or unbound orbits, conservation of angular momentum \mathbf{L} = \mu \mathbf{r} \times \dot{\mathbf{r}} (with magnitude L) allows the introduction of an effective potential governing the radial motion. The effective potential energy is given by

V_{\text{eff}}(r) = -\frac{G m_1 m_2}{r} + \frac{L^2}{2 \mu r^2},

where the first term is the gravitational potential and the second is the centrifugal barrier. This one-dimensional effective potential, combined with the radial kinetic energy, determines the turning points and overall orbital shape: elliptical for negative total energy E < 0, parabolic for E = 0, and hyperbolic for E > 0. The total energy for the relative motion is conserved as

E = \frac{1}{2} \mu \dot{r}^2 + V_{\text{eff}}(r),

providing a complete description of the radial dynamics.^[36]^[27] The solutions to this effective one-body problem generalize Kepler's laws to arbitrary mass ratios. The orbits are conic sections with the focus at the center of mass, and the semi-major axis a scales with the reduced mass through the vis-viva equation v^2 = G M \left( \frac{2}{r} - \frac{1}{a} \right). Kepler's third law becomes T^2 = \frac{4\pi^2 a^3}{G M}, where T is the orbital period and M = m_1 + m_2, reflecting the inverse-square nature of gravity independent of \mu for the period but influencing the relative orbit's energy and shape via \mu. For instance, in binary star systems, where both masses are comparable (e.g., two solar-mass stars with \mu \approx 0.5 M_\odot), the reduced mass determines the separation and eccentricity of the relative elliptical orbit, allowing astronomers to infer individual masses from observed periods and semi-major axes. In planet-satellite systems, such as Earth-Moon, \mu \approx m_{\text{Moon}} due to Earth's dominance, approximating the Moon's orbit as Keplerian around a fixed Earth.^[5]^[37]^[38]

Particle Collisions

In particle collisions, the reduced mass μ plays a central role in simplifying the analysis of momentum and energy transfer by transforming the two-body problem into an equivalent one-body problem in the center-of-mass (CM) frame. In this frame, the total momentum is zero, and the particles approach each other with relative velocity \vec{v}_{\rel} = \vec{v}_1 - \vec{v}_2, where \vec{v}_1 and \vec{v}_2 are the velocities of the two particles. The impact parameter b is defined as the perpendicular distance between the initial relative velocity vector and the line connecting the centers of the particles at large separation, which determines the closeness of the encounter. Conservation of momentum and energy in the CM frame ensures that post-collision trajectories depend on the interaction potential and initial conditions, with the reduced mass μ governing the dynamics of the relative motion, as the effective kinetic energy is \frac{1}{2} \mu v_{\rel}^2. For elastic collisions, where kinetic energy is conserved, the analysis in the CM frame reveals that the magnitude of the relative velocity remains unchanged, but its direction is altered by the collision. Along the line of centers at the point of contact, the component of the relative velocity reverses sign, ensuring the velocity of approach equals the velocity of separation. In the hard-sphere model, where particles interact only upon contact like rigid bodies, the scattering angle \theta in the CM frame is related to the impact parameter by \theta = \pi - 2 \arcsin(b / a), with a the sum of the radii, and the differential scattering cross-section d\sigma / d\Omega = (a^2 / 4) is independent of velocity, though the total cross-section \sigma = \pi a^2 incorporates the reduced mass in the relative motion kinematics. However, in contexts like collision rates for hard spheres, the effective scattering probability scales inversely with μ due to its influence on relative speeds in thermal ensembles. In inelastic collisions, kinetic energy is not conserved, and the reduced mass quantifies the energy dissipation in the relative frame. The loss in kinetic energy is given by \Delta E = \frac{1}{2} \mu (v_{\rel, \initial}^2 - v_{\rel, \final}^2), where v_{\rel, \initial} and v_{\rel, \final} are the initial and final relative speeds, respectively; this represents the conversion to internal energy such as heat or deformation. For perfectly inelastic cases, where the particles stick together, v_{\rel, \final} = 0, maximizing the loss at \Delta E = \frac{1}{2} \mu v_{\rel, \initial}^2. A classic example is the elastic collision of billiard balls of equal mass, where μ = m/2, and in the lab frame (one ball initially at rest), the CM frame simplifies calculations: post-collision, the incident ball stops, and the target moves forward, derived by adding the constant CM velocity \vec{V}_{\CM} = (m_1 \vec{v}_1 + m_2 \vec{v}_2)/(m_1 + m_2) to the reversed relative velocities in the CM frame. For subatomic scattering, such as classical approximations in neutron-proton collisions, the reduced mass (nearly m_n / 2 due to similar masses) aids in transforming lab-frame observables like deflection angles to CM-frame scattering parameters, accounting for momentum transfer.

Rotational Dynamics of Point Masses

In rotational dynamics, the reduced mass concept simplifies the analysis of two collinear point masses m_1 and m_2 separated by a fixed distance d, treated as a rigid body rotating about their center of mass (CM). The CM position is located at a distance r_1 = \frac{m_2 d}{m_1 + m_2} from m_1 and r_2 = \frac{m_1 d}{m_1 + m_2} from m_2, ensuring the rotational motion is referenced to this point for balanced dynamics.^[39] This placement follows from the definition of the CM for discrete masses, where the coordinate is the mass-weighted average of positions.^[39] The moment of inertia I about the CM for this system is I = \mu d^2, where \mu = \frac{m_1 m_2}{m_1 + m_2} is the reduced mass. This expression arises from the perpendicular distances of each mass to the rotation axis through the CM: I = m_1 r_1^2 + m_2 r_2^2. Substituting the CM distances yields I = m_1 \left( \frac{m_2 d}{m_1 + m_2} \right)^2 + m_2 \left( \frac{m_1 d}{m_1 + m_2} \right)^2 = \frac{m_1 m_2 (m_1 + m_2) d^2}{(m_1 + m_2)^2} = \mu d^2.^[40] This formulation reduces the two-body rotation to an equivalent single-body problem with mass \mu at distance d from a fixed point, leveraging the parallel axis theorem implicitly in positioning the masses relative to the CM.^[39] The rotational kinetic energy of the system is then \frac{1}{2} I \omega^2 = \frac{1}{2} \mu d^2 \omega^2, where \omega is the angular velocity. This can be interpreted in terms of relative motion, as the energy equals \frac{1}{2} \mu v_{\text{rel}}^2, with the relative tangential speed v_{\text{rel}} = d \omega. For the special case of equal masses (m_1 = m_2 = m), \mu = \frac{m}{2}, the CM lies midway, each mass is at distance \frac{d}{2} from the CM, and the tangential speed of each is v = \frac{d \omega}{2}, yielding the same energy expression.^[40] A practical example is the dumbbell model, approximating a rigid body with two point masses connected by a massless rod, or the classical treatment of a diatomic molecule where nuclear masses dominate and rotation occurs about the CM.

Quantum Applications

Two-Body Schrödinger Equation

In quantum mechanics, the two-body problem for non-interacting particles can be separated into center-of-mass and relative coordinates, analogous to the classical case. The total Hamiltonian for two particles with masses m_1 and m_2, momenta \mathbf{p}_1 and \mathbf{p}_2, and interacting via a central potential V(|\mathbf{r}_1 - \mathbf{r}_2|) is given by

H = \frac{\mathbf{p}_1^2}{2m_1} + \frac{\mathbf{p}_2^2}{2m_2} + V(|\mathbf{r}_1 - \mathbf{r}_2|).

Defining the center-of-mass position \mathbf{R} = (m_1 \mathbf{r}_1 + m_2 \mathbf{r}_2)/(m_1 + m_2) and relative position \mathbf{r} = \mathbf{r}_1 - \mathbf{r}_2, along with the total mass M = m_1 + m_2 and reduced mass \mu = m_1 m_2 / (m_1 + m_2), the Hamiltonian separates into

H = H_{\text{CM}} + H_{\text{rel}}, \quad H_{\text{CM}} = \frac{\mathbf{P}^2}{2M}, \quad H_{\text{rel}} = \frac{\mathbf{p}^2}{2\mu} + V(r),

where \mathbf{P} is the total momentum and \mathbf{p} is the relative momentum.^[41]^[19] This separation allows the center-of-mass motion to be treated as that of a free particle with mass M, while the relative motion is equivalent to a single particle with mass \mu moving in the potential V(r).^[41] The time-independent Schrödinger equation for the total wavefunction \Psi(\mathbf{r}_1, \mathbf{r}_2) is H \Psi = E \Psi. Due to the separability, the total wavefunction factors as \Psi(\mathbf{R}, \mathbf{r}) = \Phi(\mathbf{R}) \psi(\mathbf{r}), leading to independent equations for \Phi and \psi. The relative motion satisfies

-\frac{\hbar^2}{2\mu} \nabla^2 \psi(\mathbf{r}) + V(r) \psi(\mathbf{r}) = E_{\text{rel}} \psi(\mathbf{r}),

where \nabla^2 is the Laplacian in relative coordinates, and E = E_{\text{CM}} + E_{\text{rel}} with E_{\text{CM}} = \hbar^2 K^2 / (2M) for plane-wave solutions \Phi \propto e^{i \mathbf{K} \cdot \mathbf{R}}.^[41]^[19] This equation describes the dynamics of the effective one-body problem, with \mu determining the kinetic energy scale.^[42] For bound states or scattering, the relative wavefunction \psi(\mathbf{r}) is defined over an infinite domain in \mathbf{r}-space, with boundary conditions depending on the context: square-integrable \psi for bound states (ensuring normalizability) or asymptotic behavior \psi \sim e^{ikz} + f(\theta) e^{ikr}/r for scattering states at large r, where k = \sqrt{2\mu E_{\text{rel}}}/\hbar.^[41] The reduced mass \mu influences the energy eigenvalues and scales; for example, in the Coulomb potential V(r) = -Z e^2 / r, the energy levels are E_n = -\mu (Z e^2)^2 / (2 \hbar^2 n^2), leading to a Rydberg constant R = \mu e^4 / (8 \epsilon_0^2 h^3 c) that scales directly with \mu, differing from the infinite-mass value R_\infty by the factor \mu / m_e \approx 1 - m_e / m_p for hydrogen-like atoms.^[13]^[43] Although the non-relativistic framework assumes fixed \mu, relativistic corrections such as fine structure introduce adjustments to the effective mass in the Dirac equation or via perturbative terms, scaling the splitting by factors involving \mu (e.g., \alpha^2 Z^4 \mu c^2 / n^3 for the fine-structure constant \alpha).^[44] These effects highlight the role of \mu in precision spectroscopy, though the base Schrödinger equation remains non-relativistic.^[45]

Atomic and Molecular Systems

In atomic systems, the reduced mass provides a essential correction to the energy levels of hydrogen-like atoms by accounting for the finite mass of the nucleus. For the hydrogen atom, the reduced mass is defined as \mu = \frac{m_e m_p}{m_e + m_p}, which approximates to m_e (1 - m_e / m_p) since m_p \gg m_e. This refines the infinite nuclear mass approximation, scaling the bound-state energies to E_n = -\frac{\mu}{m_e} \frac{13.6 \, \mathrm{eV}}{n^2}, where the factor \mu / m_e \approx 1 - 5.45 \times 10^{-4} shifts the ground-state energy by about 7.4 meV upward from the naive value.^[8] In molecular spectroscopy of diatomic systems, the reduced mass governs the spacing of rotational and vibrational energy levels, directly impacting observed spectra. Rotational energies follow E_J = \frac{J(J+1) \hbar^2}{2 \mu r^2}, where r is the equilibrium bond length, allowing extraction of r from measured rotational constants B = \frac{\hbar^2}{2 \mu r^2}.^[46]^[47] Vibrational frequencies scale as \omega \propto \sqrt{k / \mu}, with k the force constant, such that heavier reduced masses lower transition energies and broaden spectral features.^[48] Isotopic substitution alters the nuclear mass, thereby shifting \mu and producing measurable isotope effects in spectra; for instance, deuterium's spectrum exhibits reduced vibrational frequency (by \sqrt{2} relative to hydrogen) and closer rotational spacing due to its doubled nuclear mass.^[49]^[50] In alkali atoms, the reduced mass similarly scales fine-structure splittings, with the valence electron's interaction yielding level separations proportional to \mu Z^4 \alpha^2 / n^3 (where Z is the nuclear charge and \alpha the fine-structure constant), enabling precise comparisons across isotopes.^[51] For exotic atoms like muonic hydrogen, where a muon (m_\mu \approx 207 m_e) orbits the proton, the reduced mass \mu \approx m_\mu (1 - m_\mu / m_p) \approx 0.887 m_\mu dominates due to the muon's intermediate mass scale, contracting orbits by a factor of \sim 207 and elevating X-ray transition energies to keV ranges for accurate spectral analysis.^[52] Recent relativistic calculations refine these \mu values to interpret vacuum polarization and recoil effects in such systems.^[53]

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[17]
[PDF] 2. The Lagrangian Formalism - DAMTP
We started with. 6 degrees of freedom describing the positions of two particles. Eliminating the centre of mass reduced this to 3 degrees of freedom describing ...
[18]
[PDF] Lecture 29: April 18 29.1 The two-body problem - Veit Elser
The term “reduced” is a reference to the fact that when applied to a system comprising very different masses, say M1 M2, then µ is a small reduction of the mass ...
[19]
Reduced Mass - BOOKS
Don't worry about how the particles can get past each other on the line—this is a simple toy model; just imagine that they can pass right through each other.
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Reduced Mass - Richard Fitzpatrick
(328). is called the reduced mass. Hence, we have effectively converted our original two-body problem into an equivalent one-body problem. In the equivalent ...Missing: n- | Show results with:n-
[21]
SI Units - Mass | NIST - National Institute of Standards and Technology
Mar 30, 2011 · The SI unit of mass is the kilogram (kg), defined by the Planck constant. The kilogram is the only SI base unit with a prefix.
[22]
[PDF] N-body Problem in - DSpace@MIT
Feb 5, 2018 · He realized the N = 2 problem can be reduced to a one-body problem in which the reduced mass of the two masses moves in an orbit described ...
[23]
Two-body problem
Figure 2.7: Two-body problem. (which is why it is called the “reduced” mass). We conclude that the dynamics of an isolated system consisting of two interacting ...
[24]
[PDF] 8.09(F14) Advanced Classical Mechanics - MIT OpenCourseWare
In Lagrangian mechanics, the key function is the Lagrangian. L = L(q, q˙,t) ... reduced mass for the two-body system. Thus θ = p˙θ/(µ`2) = −m2 g θ as ...
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Below is a merged response that consolidates all the information from the provided summaries into a single, comprehensive overview. To maximize detail and clarity, I will use a table in CSV format to organize the key information systematically, followed by a narrative summary that ties everything together. The table will capture the essence of each segment, including definitions, inequalities, contexts, and useful URLs, while the narrative will provide additional context and connections.
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[PDF] The two body p - City Tech OpenLab
In first approximation one can treat the system Sun-Earth as a two body problem. ... Several aspects of the study of the two body problem ... The reduced mass is ...
[27]
[PDF] 20 Lecture 11-13 - 20.1 Chapter 8 Two Body Central Force Problem
So from the point of view of the reduced mass, the gravitational interaction is an attraction to a mass equal to the total mass of both particles, M, and the.
[28]
separation of the center-of-mass motion
The treatment consists in separating the motion of the center of mass from the relative motion, in complete analogy with the corresponding classical treatment.
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[PDF] 1 Laboratory frame and center of mass frame - bingweb
Feb 1, 2021 · The separation of the system from the center of mass leads to the decrease of the degree of freedom from 6 to 3.
[30]
[PDF] PHY141 Lectures 12,13 notes
Oct 20, 2022 · where the reduced mass. µ = m1m2 m1 + m2 and the velocity difference udiff = u1 − u2. • With internal forces alone, the total momentum is ...<|control11|><|separator|>
[31]
One-Dimensional Collisions
In other words, in the center-of-mass frame, an elastic collision also causes the velocity of each particle to reverse direction, but keep the same magnitude.
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[PDF] Computation and astrophysics of the N-body problem
Internal energy of the binary (per unit reduced mass); this excludes the energy of the centre of mass of the binary. 4. Semi-major axis of the binary. 5 ...
[33]
Post-Newtonian N-body simulations - Oxford Academic
Abstract. We report on the first fully consistent conventional cluster simulation which includes terms up to the third-order post-Newtonian approximation.
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[PDF] Lecture 7 - Regularization N-body techniques for astrophysics
Nov 12, 2015 · reduced mass = 𝜇 = m1m2. M. Es. = 1 ... The codes will automatically scale the initial conditions to the centre of mass reference frame ...
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[PDF] The Two-Body problem - DAMTP
Thus, is we effectively reduced the 2-body problem to a 1-body problem. Second symmetry, isotropy of space, implies that the vector of the angular momentum ...
[36]
[PDF] 8.01SC S22 Chapter 25: Celestial Mechanics - MIT OpenCourseWare
Jun 25, 2013 · 2, then the reduced mass is approximately the smaller mass, μ ! m. 1 . In that case, the center of mass is located approximately at the ...
[37]
Binary Star Systems - Richard Fitzpatrick
... Reduced Mass. Binary Star Systems. Approximately half of the stars in our galaxy are members of so-called binary star systems. Such systems consist of two ...
[38]
[PDF] 6 The Two-Body Problem and Kepler's Laws
reduced mass µ of the two-body system, where. (46) µ ≡ m1m2 m1 + m2 and so ... Figure 7: Energy diagram for the the two-body problem, showing the contri-.
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Center of Mass; Moment of Inertia - Feynman Lectures - Caltech
The center of mass of these two point masses is then the center of mass of the whole object. ... The moment of inertia is Iz=∑imi(x2i+y2i) ...Missing: reduced | Show results with:reduced
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[PDF] Quantum Mechanics: Rotation of Diatomics: Reducing the Problem
Apr 7, 2010 · the moment of inertia in terms of the reduced mass as follows: I = m1 r2. 1 + m2 r2. 2 = µ r2. 0 where the reduced mass is defined as: µ = m1 ...
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[PDF] Quantum Physics I, Lecture Note 22 - MIT OpenCourseWare
May 4, 2016 · We get two Schrödinger equations. The first equation tells us that the center of mass moves as a free particle of mass M. Thus, the CM energy ...
[42]
[PDF] Numerical Solutions of the Schrödinger Equation - Physics
For a two-body system with a central potential, the mass m should be replaced by the reduced mass, but otherwise the equations are the same. Defining the ...
[43]
[PDF] Visible Spectrometer - UF Physics
is called the reduced mass Rydberg. If the nu- cleus were infinitely heavy, the reduced mass. µ becomes me, the mass of the electron. The combination of ...
[44]
[PDF] Quantum Physics III Chapter 2: Hydrogen Fine Structure
Apr 2, 2022 · The mass m in H(0) is the reduced mass of the electron and proton, which we can accurately set equal to the mass of the electron. If one ...
[45]
Fine Structure of Hydrogen - Richard Fitzpatrick
The lowest-order relativistic correction to the energy of a hydrogen atom state characterized by the standard quantum numbers $n$ , $l$ , and $m$ is given by
[46]
[PDF] Energy Levels of One-Electron Atoms - Standard Reference Data
Jan 21, 1974 · Simple reduced mass correction factors are already included in the lowest order radiative level shifts (2.10) and (2.11) but will not be ...<|control11|><|separator|>
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[PDF] Chapter 9. Rotational Spectroscopy
i.e., the moment of inertia is the same as that of a mass point with. H= Mi mz m, tmz at a distance r from the axis. (9) reduced mass of the molecule. Thus, ...
[48]
[PDF] Vibrational and Rotational Spectroscopy of Diatomic Molecules
In our model, the two rotating point masses with reduced mass µ will have I = µr2. ... Additionally, we can calculate the bond length of HCl from this spectrum.
[49]
[PDF] FTIR (ROTATIONAL/VIBRATIONAL) SPECTRSCOPY OF HCl
In the case of a heteronuclear diatomic molecule, equation (5) must be adjusted to accommodate two different masses. The reduced mass, μ, is substituted for m.<|control11|><|separator|>
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[PDF] The Hydrogen-Deuterium Isotope Shift - NYU Physics department
This difference arises from the different reduced masses of the nuclear-electron system in the two cases and can be used to determine the proton-deuteron mass ...
[51]
[PDF] Review of the isotope effect in the hydrogen spectrum
Enrichment of the hydrogen is necessary as the natural abundance of deuterium is about .015%. From the Rydberg formula corrected for reduced mass, Eq. (7), we ...
[52]
[PDF] Fine Structure in Hydrogen and Alkali Atoms
In these notes we consider the fine structure of hydrogen-like and alkali atoms, which concerns the effects of relativity and spin on the dynamics of the ...
[53]
[PDF] Relativistic Reduced-Mass and Recoil Corrections to Vacuum ...
Jul 11, 2011 · The results emphasize the need for a unified treatment of relativistic corrections to vacuum polarization in muonic hydrogen, muonic deuterium,.
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Relativistic reduced-mass and recoil corrections to vacuum ...
The reduced-mass dependence of relativistic and radiative effects in simple muonic bound systems is investigated. The spin-dependent nuclear recoil ...