Truncated tetrahedron
A truncated tetrahedron is an Archimedean solid formed by cutting off the vertices of a regular tetrahedron such that each original triangular face becomes a regular hexagon and new equilateral triangular faces appear at the truncated vertices, resulting in a convex polyhedron with 4 regular triangular faces, 4 regular hexagonal faces, 12 vertices, and 18 edges.[1][2] This uniform polyhedron, with Schläfli symbol t{3,3}, exhibits full tetrahedral symmetry and is one of the 13 Archimedean solids, where all vertices are congruent and surrounded by the same arrangement of faces (one triangle and two hexagons).[1][3] Its dual is the triakis tetrahedron, and it can be inscribed in a sphere, with geometric properties including a surface area of $7\sqrt{3}a^2 and volume of \frac{23}{12}\sqrt{2}a^3 for edge length a.[1] Historically, the truncated tetrahedron was illustrated by Leonardo da Vinci in Luca Pacioli's De Divina Proportione (1509) and featured in Albrecht Dürer's nets (1525) and Johannes Kepler's Harmonices Mundi (1619), highlighting its role in early studies of polyhedral geometry.[3]Definition and Construction
Overview
The truncated tetrahedron is a uniform Archimedean solid formed by truncating the vertices of a regular tetrahedron, which replaces the original triangular faces with regular hexagons while introducing new regular triangular faces at the truncated vertices, resulting in 4 regular triangular faces and 4 regular hexagonal faces.[1][3] This convex polyhedron has 12 vertices, 18 edges, and 8 faces in total, verifying the Euler characteristic for convex polyhedra as V - E + F = 12 - 18 + 8 = 2.[4] At each vertex, the faces meet in an identical configuration of one equilateral triangle and two regular hexagons, denoted as (3.6.6).[1][5] The truncated tetrahedron exhibits full tetrahedral symmetry, belonging to the point group T_d of order 24, and is classified as a semi-regular polyhedron due to its vertex-transitive nature and regular polygonal faces.[6] It was studied and illustrated in the context of Archimedean solids by Johannes Kepler in his 1619 work Harmonices Mundi.[3]Construction Methods
The truncated tetrahedron is constructed primarily through the truncation of a regular tetrahedron, a process that involves cutting off each of the four vertices at a depth equal to one-third the length of the original edges. This truncation transforms the original triangular faces into regular hexagons by removing the corners, while introducing new equilateral triangular faces at the sites of the truncated vertices. The resulting polyhedron maintains uniformity, with all edges of equal length and faces meeting in the regular vertex configuration of one triangle and two hexagons.[7][8] In this construction, each original vertex of the tetrahedron is replaced by a new triangular face, and the remnants of the original edges—now reduced to one-third their initial length—alternate with the new edges from the truncation cuts to form the sides of the hexagonal faces. This method ensures the polyhedron's Archimedean properties, as the truncation depth precisely balances the edge lengths for regularity.[7][9] An alternative mathematical construction arises from the Wythoff process applied to the tetrahedral symmetry group, yielding the uniform polyhedron U_6 with Wythoff symbol $2\, 3 \mid 3. This symbol indicates the positions of vertices relative to the mirrors of the Coxeter diagram for the tetrahedral group, generating the truncated tetrahedron directly from the regular tetrahedron's symmetry. Equivalently, it corresponds to the Schläfli symbol t\{3,3\}, denoting the truncation operation on the tetrahedron, with the vertex figure described as 3.6.6.[1][10] For tangible models, the truncated tetrahedron can be assembled from a net comprising four equilateral triangles and four regular hexagons arranged in a non-overlapping layout suitable for folding, such as a chain of hexagons with triangles attached to alternate edges to form the closed surface without gaps or overlaps.[1]Geometric Properties
Cartesian Coordinates
A truncated tetrahedron centered at the origin can be described using 12 vertices obtained from all even permutations of the coordinates (\pm 1, \pm 1, \pm 3), where the choice of signs results in an even number of negative signs overall. This configuration ensures the tetrahedral symmetry of the polyhedron.[11] In this unscaled form, the edge length is \sqrt{8}. To achieve a unit edge length, scale all coordinates by the factor \frac{1}{\sqrt{8}} = \frac{1}{2\sqrt{2}}. The resulting vertices are all even permutations of \left( \pm \frac{\sqrt{2}}{4}, \pm \frac{\sqrt{2}}{4}, \pm \frac{3\sqrt{2}}{4} \right) with an even number of negative signs.[12] Equivalently, the 12 vertices for unit edge length can be generated as all permutations of \left( \frac{3\sqrt{2}}{4}, \frac{\sqrt{2}}{4}, \frac{\sqrt{2}}{4} \right) with an even number of sign changes (i.e., even parity of negative signs). This set maintains the required symmetry and positions the polyhedron with its center at the origin.[12] To verify the edge length, consider two adjacent vertices in the scaled form, such as \left( \frac{3\sqrt{2}}{4}, \frac{\sqrt{2}}{4}, \frac{\sqrt{2}}{4} \right) and \left( \frac{\sqrt{2}}{4}, \frac{3\sqrt{2}}{4}, \frac{\sqrt{2}}{4} \right). The Euclidean distance between them is \sqrt{ \left( \frac{3\sqrt{2}}{4} - \frac{\sqrt{2}}{4} \right)^2 + \left( \frac{\sqrt{2}}{4} - \frac{3\sqrt{2}}{4} \right)^2 + 0^2 } = \sqrt{2 \left( \frac{\sqrt{2}}{2} \right)^2 } = \sqrt{2 \cdot \frac{1}{2}} = 1, confirming the normalization.[12]Dimensions and Formulas
The surface area A of a uniform truncated tetrahedron with edge length a is given by A = 7\sqrt{3}\, a^{2}. This formula arises from the contribution of its eight faces: four equilateral triangular faces, each with area \frac{\sqrt{3}}{4} a^{2} for a total of \sqrt{3}\, a^{2}, and four regular hexagonal faces, each with area \frac{3\sqrt{3}}{2} a^{2} for a total of $6\sqrt{3}\, a^{2}.[1] The volume V is V = \frac{23\sqrt{2}}{12} a^{3} \approx 3.0792 a^{3}, or equivalently V = \frac{23}{12} \sqrt{2}\, a^{3}. One derivation decomposes the solid as a regular tetrahedron of edge length $3a with four smaller regular tetrahedra of edge length a removed from its vertices; the volume of a regular tetrahedron of edge b is \frac{\sqrt{2}}{12} b^{3}, yielding \frac{\sqrt{2}}{12} (3a)^{3} - 4 \cdot \frac{\sqrt{2}}{12} a^{3} = \frac{27\sqrt{2}}{12} a^{3} - \frac{4\sqrt{2}}{12} a^{3} = \frac{23\sqrt{2}}{12} a^{3}.[1] In the uniform truncated tetrahedron, all 18 edges have equal length a. The circumradius R, or distance from the center to a vertex, is R = \frac{\sqrt{22}}{4} a \approx 1.1726 a. The midradius \rho, or distance from the center to the midpoint of an edge (also the radius of the midscribed sphere tangent to all edges), is \rho = \frac{3\sqrt{2}}{4} a \approx 1.0607 a. These measures, along with the face-center distances below, can be computed using the Cartesian coordinates of the vertices.[1] The distances from the center to the centers of the faces differ by face type. For each triangular face, this distance (sometimes termed the triangular face radius) is \frac{5\sqrt{6}}{12} a \approx 1.0206 a. For each hexagonal face, it is \frac{\sqrt{6}}{4} a \approx 0.6124 a. Note that the truncated tetrahedron lacks a single inscribed sphere tangent to all faces, as these perpendicular distances to the face planes vary.[6]Dihedral Angles
The dihedral angles of the truncated tetrahedron are the angles between adjacent faces, which occur in two types due to the mix of triangular and hexagonal faces. The dihedral angle between a hexagonal face and a triangular face is given by \arccos\left(-\frac{1}{3}\right), approximately 109.47122°.\] This angle arises along the edges where a new [triangular face](/page/Triangular_face), formed by truncating an original [vertex](/page/Vertex), meets a hexagonal face derived from an original [triangular face](/page/Triangular_face).\[ In contrast, the dihedral angle between two adjacent hexagonal faces is \arccos\left(\frac{1}{3}\right), approximately 70.52878°.$$] These angles reflect the geometry preserved from the parent tetrahedron while introducing new interfaces from the truncation process. These dihedral angles can be computed using the normal vectors to the adjacent faces, derived from the Cartesian coordinates of the polyhedron. For instance, placing the truncated tetrahedron in a coordinate system with vertices at points like (1,1,3) and permutations scaled appropriately allows calculation of face normals via cross products of edge vectors; the angle between normals then yields the dihedral angle via the dot product formula \cos \theta = -\mathbf{n_1} \cdot \mathbf{n_2} / (|\mathbf{n_1}| |\mathbf{n_2}|), adjusted for the interior angle.[$$ This method confirms the exact expressions above and is standard for uniform polyhedra. Compared to the regular tetrahedron, which has a uniform dihedral angle of \arccos\left(\frac{1}{3}\right) \approx 70.53° between all faces,\] [truncation](/page/Truncation) preserves this angle between the hexagonal faces (corresponding to original face planes) but introduces the larger 109.47122° angle at the new edges, effectively "opening up" the structure at the vertices to accommodate the cutting planes.\[ Both angles being less than 180° ensures the polyhedron remains convex, as the faces fold inward without reflex angles that would imply concavity.[]Combinatorial and Symmetrical Aspects
Face-Edge-Vertex Configuration
The truncated tetrahedron possesses 8 faces, comprising 4 equilateral triangles and 4 regular hexagons, along with 18 edges and 12 vertices.[1] Its Schläfli symbol is t\{3,3\}, denoting the truncation of the regular tetrahedron \{3,3\}.[1] As a uniform Archimedean solid, it exhibits a density of 1, indicating a simply connected interior without overlaps or holes.[5] Each of the 12 vertices has degree 3, where one triangular face and two hexagonal faces meet, corresponding to the vertex configuration (3.6.6).[1] This uniform vertex figure ensures identical arrangements at every vertex. The edges divide into two categories: 12 edges connecting a triangle to a hexagon, introduced by the truncation at the original vertices, and 6 edges connecting two hexagons, remnants of the original tetrahedral edges now shortened and bounded by the expanded faces.[13] The facial adjacencies reflect the truncation process: each triangular face, arising from an original vertex, borders exactly three hexagonal faces, with no two triangles sharing an edge.[13] Conversely, each hexagonal face, derived from an original triangular face, adjoins three triangular faces (at the sites of the original vertices) and three other hexagonal faces (along the original edges). This configuration positions the four hexagons such that every pair shares an edge, while the triangles remain isolated from one another.[13]Symmetry Group
The symmetry group of the truncated tetrahedron is the full tetrahedral point group T_d, which consists of 24 elements and describes all isometries that map the polyhedron to itself.[14] This group extends the chiral rotational subgroup T of order 12 by including improper isometries such as reflections and rotary reflections.[13] The rotational symmetries comprise the identity element, eight C_3 rotations (by $120^\circ and $240^\circ) about four axes that pass through the centers of the triangular faces and the center of the polyhedron, and three C_2 rotations (by $180^\circ) about three axes that pass through the midpoints of pairs of opposite edges.[13] The full T_d group further includes six S_4 improper rotations (by $90^\circ and $270^\circ) about the same three axes as the C_2 rotations, and six dihedral reflections \sigma_d in planes that each contain one edge of a hexagonal face and bisect the angle at the adjacent vertices.[15] The presence of reflection planes renders the truncated tetrahedron achiral, the same as for the regular tetrahedron from which it is derived. Truncation preserves the overall tetrahedral symmetry but relocates the axes relative to the new facial structure: the C_3 axes align with the triangular faces (corresponding to the original vertices), while the C_2 and S_4 axes relate to the geometry of the hexagonal faces and edges.[13] Under the action of the T_d group, the 12 vertices form a single orbit (isogonal property), and the 18 edges form a single orbit (isotoxal property).[14] The four triangular faces form one orbit, and the four hexagonal faces form a separate orbit, reflecting the distinct roles of these face types in the symmetry.[13]Dual and Graph Theory
Dual Polyhedron
The dual polyhedron of the truncated tetrahedron is the triakis tetrahedron, a Catalan solid consisting of 12 isosceles triangular faces, 8 vertices, and 18 edges. The 12 faces of the triakis tetrahedron correspond to the 12 vertices of the truncated tetrahedron, while its 8 vertices correspond to the 8 faces of the primal polyhedron: specifically, 4 vertices of degree 3 arising from the 4 triangular faces and 4 vertices of degree 6 from the 4 hexagonal faces.[16][1] This configuration ensures that the dual inherits the full tetrahedral symmetry group T_d of the truncated tetrahedron.[16] As a Catalan solid, the triakis tetrahedron is isohedral, with all faces congruent and equivalent under the symmetry operations, though the faces are not regular triangles.[17] Each face is an isosceles triangle, and the edges consist of 12 shorter edges and 6 longer edges when normalized to the dual of a unit-edge truncated tetrahedron.[16] The solid was first described by Eugène Catalan in his seminal work on polyhedra.[16] The vertices of the triakis tetrahedron are positioned along the outward normals to the faces of the truncated tetrahedron, scaled such that the dual edges connect properly and the polyhedron is convex.[16] This construction preserves the midsphere shared between the primal and dual, tangent to all edges of both.[1] Additionally, the triakis tetrahedron can be viewed as the kleetope of a regular tetrahedron, obtained by attaching a triangular pyramid to each of the four faces of the base tetrahedron, with the pyramid height chosen to produce isosceles triangular faces on the resulting solid.[18]Truncated Tetrahedral Graph
The truncated tetrahedral graph is the 1-skeleton of the truncated tetrahedron, featuring 12 vertices each of degree 3 connected by 18 edges. As a cubic Archimedean graph, it is 3-regular, 3-vertex-connected, and planar, embedding as a polyhedral graph on the sphere with topological genus 0.[19] This graph is vertex-transitive, with its automorphism group of order 24 isomorphic to the full tetrahedral group T_d, reflecting the symmetries of the underlying polyhedron. It is Hamiltonian, admitting a cycle that visits each vertex exactly once; as a cubic Hamiltonian graph, it can be compactly described using LCF notation [2, 6, -2]^4.[19] The spectral properties of the graph are characterized by the eigenvalues of its adjacency matrix: $3^1, 2^3, 0^2, (-1)^3, (-2)^3, making it an integral graph with integer eigenvalues. Due to the presence of triangular cycles (girth 3), the graph is not bipartite and has chromatic number 3, requiring three colors for a proper vertex coloring.[19][20]Related Polyhedra
Within Archimedean Solids
The truncated tetrahedron is one of the 13 Archimedean solids, defined as convex uniform polyhedra featuring regular polygonal faces of two or more types, vertex-transitive symmetry where the same sequence of faces meets at each vertex, and all edges of equal length.[21] These solids exclude the five Platonic solids, infinite prisms, and antiprisms, focusing instead on semi-regular forms with high symmetry.[21] In standard enumerations, such as the Wenninger polyhedron models, the truncated tetrahedron appears as the sixth entry.[1] What distinguishes the truncated tetrahedron within this family is its origin from the regular tetrahedron through truncation, resulting in the only Archimedean solid that combines equilateral triangular and regular hexagonal faces while retaining full tetrahedral symmetry (Td group).[1] This contrasts with other Archimedean solids derived from cubic/octahedral symmetries (e.g., truncated cube with triangles and octagons) or icosahedral/dodecahedral symmetries (e.g., truncated icosahedron with pentagons and hexagons), highlighting its unique tetrahedral heritage and face pairing.[13] The 13 solids were originally described by the ancient Greek mathematician Archimedes around the 3rd century BCE, though he did not claim discovery; the complete set was systematically cataloged and named by Johannes Kepler in his 1619 treatise Harmonices Mundi.[22] Kepler's work emphasized their uniformity and placed them alongside truncated forms like the truncated octahedron and truncated cuboctahedron, all unified by equal edges and regular faces.[23] The following table summarizes the face configurations of all 13 Archimedean solids using Wythoff-Schläfli notation, where {n} denotes the number and type of regular n-gons (e.g., 4{3} + 4{6} for four triangles and four hexagons in the truncated tetrahedron).[21]| Solid Name | Face Configuration |
|---|---|
| Truncated tetrahedron | 4{3} + 4{6} |
| Cuboctahedron | 8{3} + 6{4} |
| Truncated cube | 8{3} + 6{8} |
| Truncated octahedron | 6{4} + 8{6} |
| Rhombicuboctahedron | 8{3} + 18{4} |
| Truncated cuboctahedron | 12{4} + 8{6} + 6{8} |
| Snub cube | 32{3} + 6{4} |
| Icosidodecahedron | 20{3} + 12{5} |
| Truncated dodecahedron | 20{3} + 12{10} |
| Truncated icosahedron | 20{6} + 12{5} |
| Rhombicosidodecahedron | 20{3} + 30{4} + 12{5} |
| Truncated icosidodecahedron | 30{4} + 20{6} + 12{10} |
| Snub dodecahedron | 80{3} + 12{5} |