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Halting problem

The halting problem is a decision problem in computability theory that asks whether there exists a general algorithm capable of determining, for any given computer program and input, if the program will eventually halt (terminate) or continue running indefinitely.^[1] This problem, first formally analyzed by Alan Turing, reveals inherent limitations in mechanical computation, as no such universal algorithm can exist for all possible programs and inputs.^[2] Turing introduced the halting problem in his seminal 1936 paper, "On Computable Numbers, with an Application to the Entscheidungsproblem," where he modeled computation using abstract machines—now called Turing machines—to define what it means for a number or function to be computable.^[2] To prove its undecidability, Turing employed a diagonalization argument: assuming a halting oracle exists leads to a contradiction, as one can construct a program that behaves oppositely to the oracle's prediction on itself, resulting in a logical paradox.^[2] This proof not only settled the Entscheidungsproblem—David Hilbert's question of whether there is an algorithm to determine the truth of any mathematical statement in first-order logic—but also established the foundations of modern computability theory.^[2] The implications of the halting problem extend far beyond its initial context, underscoring that certain problems are intrinsically unsolvable by any computational process, no matter how powerful.^[3] It serves as a cornerstone for demonstrating the undecidability of related issues, such as the totality problem (determining if a program halts on all inputs) and problems in program verification, compiler design, and artificial intelligence.^[3] In practice, while specific instances of the halting problem can often be resolved through analysis or timeouts, the general case's undecidability highlights the boundaries of automation in software engineering and theoretical mathematics, influencing fields from formal verification.^[4]

Fundamentals

Informal Description

The halting problem concerns whether it is possible to devise a general procedure that, for any given computer program and input, can determine if the program will eventually stop running or continue indefinitely. This question captures a fundamental limit on what computers can compute about their own behavior, as programs can encode arbitrarily complex processes that may loop forever without producing an output.^[2] A relatable analogy appears in everyday programming challenges, such as determining if a loop will terminate. For instance, the Collatz conjecture describes a simple rule: start with any positive integer, and if it is even, divide by 2; if odd, multiply by 3 and add 1; repeat the process. Despite extensive verification for large numbers, no proof exists that this always reaches 1 and stops, highlighting how even straightforward iterative algorithms can defy prediction of termination. The difficulty stems from the fact that programs can mimic the execution of other programs, creating scenarios of self-reference where a halting predictor might need to analyze itself, leading to paradoxes and an inability to resolve all cases algorithmically. Alan Turing introduced this problem in 1936 as part of his response to the Entscheidungsproblem—the challenge posed by David Hilbert and Wilhelm Ackermann in 1928 to find a mechanical method for deciding the truth of any mathematical statement in first-order logic.^[2]^[5]

Turing Machines

A Turing machine serves as the foundational abstract model of computation, providing a precise framework for defining what it means for a function or procedure to be effectively calculable. Introduced by Alan Turing in his 1936 paper, it simulates the process of a human computer following a set of instructions to manipulate symbols on paper.^[6] This model underpins modern computability theory by capturing the intuitive notion of step-by-step mechanical computation without relying on specific physical implementations. The essential components of a Turing machine include an infinite tape, a read/write head, a finite state control unit, and a transition function. The tape is an unbounded one-dimensional strip divided into discrete cells, each capable of storing a single symbol from a finite set known as the tape alphabet; initially, all cells beyond the input are blank. The read/write head positions itself on one cell at a time, allowing it to erase or overwrite the current symbol and then move left, right, or remain in place. The finite state control maintains one of a limited number of internal states, reflecting the machine's "configuration" at each step. The transition function governs the machine's operation by specifying, based on the current state and the symbol under the head, what symbol to write, which direction to move the head, and what the next state will be.^[7] Formally, a Turing machine M is defined as a 7-tuple M = (Q, \Sigma, \Gamma, \delta, q_0, q_{\text{accept}}, q_{\text{reject}}), where:

Q is a finite set of states,
\Sigma is the finite input alphabet (not containing the blank symbol),
\Gamma is the finite tape alphabet with \Sigma \subseteq \Gamma and a blank symbol \sqcup \in \Gamma,
\delta: Q \times \Gamma \to Q \times \Gamma \times \{L, R\} is the partial transition function,
q_0 \in Q is the start state,
q_{\text{accept}} \in Q is the accept state, and
q_{\text{reject}} \in Q is the reject state (with q_{\text{accept}} \neq q_{\text{reject}}).

The computation begins with the input string from \Sigma placed on the tape starting at the leftmost cell, the head positioned on the first symbol, and the machine in state q_0; it proceeds by applying \delta repeatedly until entering q_{\text{accept}}, q_{\text{reject}}, or a state with no defined transition.^[8] To illustrate, consider a simple Turing machine that copies its input string of 0s and 1s, producing the original followed by a special marker 'c' and then an exact duplicate. Starting in state q_1, the machine scans right over the input until reaching a blank, writing 'c' and shifting to q_2 to move left. In the main loop (state q_3), it marks the current input symbol (0 as 'd' or 1 as 'e'), moves right to the copy area after 'c', and writes the original symbol (state q_4 for 0 or q_5 for 1) at the first blank encountered. It then returns left (state q_6), restores the marked symbol to its original, and repeats until all input is processed, finally halting in q_8 with the head at the start. The full set of transitions, such as (q_3, 0) \to (write 'd', right, q_4), ensures the copy is built sequentially without overwriting the original.^[9] Turing machines are computationally equivalent to other foundational models, including Alonzo Church's lambda calculus and recursive function theory, in the sense that any procedure expressible in one can be simulated by the others with only polynomial overhead in resources.^[10] This equivalence supports the Church-Turing thesis, which asserts that the Turing machine captures the full extent of what is computable by any effective, finite procedure—encompassing all algorithmic methods feasible for human computation.^[11]

Historical Development

Precursors to Turing

The Entscheidungsproblem, or decision problem, was formally posed by David Hilbert and Wilhelm Ackermann in their 1928 book Grundzüge der theoretischen Logik, challenging mathematicians to develop an algorithm that could mechanically determine the validity of any statement in first-order predicate logic.^[12] This problem encapsulated Hilbert's broader program for formalizing mathematics, aiming to establish a complete and consistent axiomatic system where all truths could be algorithmically verified or refuted. In 1931, Kurt Gödel's incompleteness theorems profoundly impacted this quest by demonstrating inherent limitations in formal systems. Gödel's first theorem showed that in any consistent formal system capable of expressing basic arithmetic, there exist true statements that cannot be proved within the system itself, as detailed in his seminal paper "Über formal unentscheidbare Sätze der Principia Mathematica und verwandter Systeme I," published in Monatshefte für Mathematik und Physik.^[13] The second theorem extended this by proving that such a system cannot prove its own consistency, underscoring the undecidability of certain propositions and challenging the feasibility of Hilbert's vision for algorithmic provability. Building on these foundations, Alonzo Church developed the lambda calculus between 1932 and 1936 as a model of computation and logical foundation. In his 1932 paper "A Set of Postulates for the Foundation of Logic," Church introduced lambda abstraction as a means to define functions anonymously, evolving it into a full system by 1933 that supported higher-order functions and recursion. Concurrently, Church explored recursive functions, proposing in his 1934 work that lambda-definable functions capture all effectively computable ones, a precursor to his later thesis on computability.^[14] These developments provided alternative frameworks to Turing machines for analyzing algorithmic processes, emphasizing functional abstraction over mechanical simulation. In early 1936, Church published "A Note on the Entscheidungsproblem" in the Journal of Symbolic Logic, proving the undecidability of first-order predicate logic by reducing it to the non-recursive nature of certain predicates, thus providing a negative resolution to Hilbert's challenge just as Turing's independent work appeared. This result, building on his lambda calculus and recursive function theory, highlighted the boundaries of algorithmic decision-making in logic and influenced subsequent computability research.

Turing's 1936 Paper

In 1936, Alan Turing published his seminal paper titled "On Computable Numbers, with an Application to the Entscheidungsproblem" in the Proceedings of the London Mathematical Society (Series 2, Volume 42, Issue 1, pages 230–265), received on 28 May and read on 12 November of that year.^[2] Turing's primary motivation was to address David Hilbert's Entscheidungsproblem, posed in 1928 as part of Hilbert's program to formalize mathematics and determine whether there exists a general algorithm to decide the truth of any mathematical statement within a formal system. Influenced by Kurt Gödel's 1931 incompleteness theorems, which demonstrated limitations in formal axiomatic systems, Turing sought to define the notion of "computable" precisely by modeling computation through idealized machines, thereby showing that no such general decision procedure exists.^[2] In the paper, Turing introduced the concept of computable numbers as those real numbers whose infinite decimal expansions can be generated by a finite algorithmic process, contrasting them with non-computable numbers that cannot be effectively calculated despite being mathematically definable. To formalize this, he described a theoretical device now known as the Turing machine, consisting of an infinite tape divided into squares, a read-write head, and a finite set of states, capable of performing computations by manipulating symbols on the tape according to a fixed table of instructions. Central to his framework was the universal Turing machine, a single machine that could simulate the behavior of any other Turing machine given its complete description as input, enabling the encoding and execution of arbitrary computable processes.^[2] The halting problem, referred to by Turing as the "circle" problem, is explicitly posed in Section 8 of the paper (pages 246–248), where he questions whether there exists a general method to determine if a given Turing machine, starting from a specific configuration, will eventually halt (being "circle-free") or enter an infinite loop (being "circular"). Turing provided an informal argument sketch grounded in his earlier analogy of human computation: he envisioned a human "computer" performing calculations by writing symbols on an infinite sheet of paper divided into squares, observing only a finite portion at a time and operating in discrete states of mind, with movements limited to a fixed distance. This setup underscores the mechanizability of computation but leads to the insight that no such human or machine process can reliably predict its own termination without risking paradox, as assuming a decider machine for halting would allow constructing a contradictory self-referential case.^[2]

Formalization

Decision Problem

The halting problem is formally defined as the question of whether, given a Turing machine M and an input string w, the machine M will eventually halt (terminate) when started on w.^[2] This decision problem captures the fundamental limits of algorithmic determination regarding the termination behavior of computational processes modeled by Turing machines.^[2] In precise terms, the halting problem corresponds to the set

\text{HALT} = \{ \langle M, w \rangle \mid M \text{ is a Turing machine that halts on input } w \},

where \langle M, w \rangle denotes a standard encoding of the Turing machine M and its input w as a single string over a finite alphabet, such as binary.^[15] Membership in HALT means that simulating M on w reaches a halting state after finitely many steps, without entering an infinite computation.^[15] As a decision problem, the halting problem is equivalent to determining whether a given encoded pair \langle M, w \rangle belongs to the language HALT over the alphabet of possible encodings.^[15] This frames it within the theory of formal languages and automata, where a decider for HALT would be a Turing machine that accepts exactly the strings in HALT and rejects those not in it.^[15] Turing machines provide the foundational model for this language recognition task, as they formalize the notion of effective computation.^[2] The computations performed by Turing machines yield partial recursive functions, which are functions from natural numbers (or strings) to natural numbers that may be undefined on some inputs if the machine fails to halt.^[15] A function is total recursive if it halts on all inputs, but many partial recursive functions are not total, precisely because halting is not guaranteed.^[15] The halting problem thus inquires whether the partial function computed by M is defined (i.e., halts) at the specific input w.^[15] Trivial examples illustrate the problem's scope: a Turing machine M that immediately enters a halting state without reading its input belongs to HALT for every w, as it always terminates in zero or one step.^[15] Conversely, a machine programmed to enter an infinite loop—such as repeatedly writing a symbol and moving right without any halting condition—does not halt on any input, so \langle M, w \rangle \notin HALT for all w.^[15] These cases highlight how the problem distinguishes terminating from non-terminating behaviors in simple scenarios, though it becomes intractable for general machines.^[15] In the arithmetical hierarchy—a classification of subsets of natural numbers based on the complexity of their definitions in first-order arithmetic—the set HALT resides at the lowest nontrivial level, \Sigma^0_1.^[16] The \Sigma^0_1 class consists of recursively enumerable sets, which can be expressed by formulas of the form \exists x \, \phi(n, x), where \phi is a computable predicate and n is a free variable representing elements of the set; for HALT, membership holds if there exists a finite computation trace leading to halting.^[16] This placement underscores that while HALT is "semidecidable" (one can confirm halting by simulation but not non-halting), it exceeds the decidable sets, which form the \Delta^0_1 level.^[16]

Reduction to Self-Reference

To formalize the halting problem in a way that enables a proof via self-reference, Turing machines must first be encoded as finite strings over a fixed alphabet, allowing them to serve as inputs to other machines. This encoding, analogous to Gödel numbering for formal systems, represents the machine's states, symbols, transitions, and initial configuration as a unique "description number" or string, such as by mapping components to binary or decimal sequences. For instance, states and tape symbols are assigned numerical codes, and the transition function is serialized into a single string \langle M \rangle, ensuring that every Turing machine M has a computable encoding that captures its entire behavior.^[2]^[17] Building on this encoding, a universal Turing machine U can be constructed to simulate the execution of any Turing machine M on any input w, given the pair \langle M, w \rangle as its own input. The universal machine U operates by interpreting the encoded description \langle M \rangle, reconstructing M's transition table, and iteratively updating a simulated tape and state to mimic M's computation steps on w, effectively computing the partial function U(\langle M, w \rangle) = M(w). This simulation is computable and requires only a fixed, finite set of instructions in U, independent of M, demonstrating that the class of Turing-computable functions is closed under encoding.^[2]^[17] The reduction to self-reference proceeds by assuming the existence of a decider H for the halting problem, which takes \langle M, w \rangle and determines whether M halts on w. Using this H and the universal machine, one can define a Turing machine D that takes an encoded machine \langle M \rangle as input and behaves oppositely to H's prediction on the self-input: D halts on \langle M \rangle if H(\langle M, \langle M \rangle \rangle) indicates that M does not halt on \langle M \rangle, and D loops on \langle M \rangle if H indicates that M does halt on \langle M \rangle. Thus, D(\langle M \rangle) inverts the halting behavior predicted by H for M on \langle M \rangle. Applying this to D's own description \langle D \rangle via H—considering H(\langle D, \langle D \rangle \rangle)—yields a self-referential contradiction, as the prediction cannot consistently match D's defined behavior. This setup leverages the encodings to reduce the general halting problem to the special case of deciding halting on self-encodings, generating the paradoxical self-application under the assumption of H.^[2]^[17] Self-reference is essential here because the universal machine's simulation capability, combined with the assumed decider H, allows the proof to internalize the contradiction within the Turing machine model. By encoding machines as data, the construction ensures that self-referential inputs like \langle M, \langle M \rangle \rangle are valid and computably generatable, mirroring Cantor's diagonal argument but adapted to computational processes.^[2]^[17]

Proof of Undecidability

Diagonalization Method

The diagonalization method is a proof technique originally developed by Georg Cantor to demonstrate the uncountability of the real numbers, where an assumed enumeration of all reals is contradicted by constructing a new real that differs from each listed number in at least one decimal place along the diagonal of the enumeration table.^[18] In the context of computability, Alan Turing adapted a similar diagonal argument in his 1936 paper to show that not all real number sequences are computable, by assuming an enumeration of computable sequences and constructing a contradictory sequence that diverges from the assumed list on the diagonal positions.^[2] This method exploits the countability of Turing machines, which can be enumerated as a list M_1, M_2, \dots via their finite descriptions, to reveal inherent limitations in mechanical computation.^[19] Applied to the halting problem, the diagonalization technique proceeds by considering an infinite table where rows correspond to all possible Turing machines M_i and columns to all possible inputs w_j, typically encoded as descriptions \langle M_j \rangle, with each entry indicating whether M_i halts (or accepts, in the related acceptance problem) on w_j.^[20] Assume a hypothetical halting solver H exists that decides this table completely, outputting "halt" or "loop" for every entry. To derive a contradiction, construct a new Turing machine D—the "diagonal" machine—that, on input \langle M_i \rangle, simulates or queries H on the pair (\langle M_i \rangle, \langle M_i \rangle) (the diagonal entry) and then behaves oppositely: if H predicts halting, D loops indefinitely; if H predicts looping, D halts immediately.^[18] This flip ensures D differs from every M_i in the enumeration on the specific input \langle M_i \rangle, particularly its own description \langle D \rangle, where applying H to predict D's behavior on \langle D \rangle leads to inconsistency—D cannot both halt and loop as required.^[19] The method succeeds because Turing machines form a countable set, allowing their complete enumeration in such a table, while the diagonal construction produces a machine whose halting behavior cannot be captured by any entry in the assumed solvable table, proving no such H can exist.^[2] This self-referential diagonal flip, enabled by the encoding of machines as inputs, directly undermines the assumption of decidability without relying on external simulations.^[20]

Contradiction via Universal Machine

To complete the proof of undecidability, assume for contradiction that a Turing machine H exists that solves the halting problem: given the standard description (S.D.) of any Turing machine M and an input, H determines whether M halts on that input by outputting a specific symbol, such as "s" for halting (circle-free) or "u" for non-halting (circular).^[2] This H effectively decides if the computation enters a repeating cycle or terminates.^[2] Now consider the universal Turing machine U, which can simulate the behavior of any Turing machine M given only M's S.D. and an input encoded as a sequence of symbols on its tape.^[2] The simulation by U involves interpreting the S.D. to mimic M's transitions, adding a finite number of states and symbols to account for the encoding and decoding process; however, this overhead does not alter the fundamental halting behavior, as U will halt if and only if the simulated M halts, allowing H to inspect the simulation's outcome.^[2] To derive the contradiction, construct a new machine K whose S.D. incorporates H and U: K takes as input the S.D. of some machine N, uses H to test if N halts on its own S.D. as input, and if H outputs "s" (indicating N halts), K enters an infinite loop by repeatedly printing a fixed symbol without stopping; conversely, if H outputs "u" (indicating N does not halt), K immediately halts.^[2] Apply K to its own S.D., denoted \langle K \rangle: run H on \langle K \rangle via U's simulation. If H decides that K halts on \langle K \rangle, then by K's construction, K loops infinitely, contradicting H's decision. If H decides that K does not halt on \langle K \rangle, then K halts immediately, again contradicting H's decision.^[2] This covers all cases, as every computation either halts or runs forever without repetition (in Turing's model, non-halting implies a circular state), and the self-referential input ensures the simulation faithfully captures the behavior without external interference.^[2] Thus, no such H can exist, establishing that the halting problem is undecidable.^[2]

Implications in Computability

Links to Incompleteness Theorems

The undecidability of the halting problem implies incompleteness in formal systems capable of expressing basic arithmetic, as instances of the halting problem can be encoded as arithmetic statements within such theories. Specifically, for a consistent, effectively axiomatized theory T that interprets Robinson arithmetic Q, the halting question for a Turing machine m on input x translates to a \Pi_1 sentence in the language of arithmetic, asserting that no computation step leads to a halting state. Since the halting problem is undecidable, T cannot prove all true such sentences, yielding an unprovable true statement and thus incompleteness.^[21] Turing's 1936 proof of the halting problem's undecidability can be viewed as a model-theoretic analogue to Gödel's 1931 syntactic argument for incompleteness, both employing diagonalization to construct self-referential paradoxes. While Gödel's construction yields a sentence asserting its own unprovability within Peano arithmetic, Turing's diagonal argument over Turing machines produces a machine that behaves oppositely to any purported halting oracle, revealing limits in effective procedures. This parallel underscores how both results exploit self-reference to expose boundaries in formal and computational systems. A key corollary is that no consistent theory T extending Q can prove all instances of the halting problem for a sound system, as such provability would yield a decision procedure contradicting undecidability. If T is \omega-consistent, the sentence encoding non-halting for a self-referential machine remains unprovable, mirroring Gödel's undecidable sentence. This extends to the second incompleteness theorem: T cannot prove its own consistency, as that would imply proving all halting instances, which is impossible.^[22]^[21] In modern metamathematics, both the halting problem and Gödel's theorems illustrate the pervasive power of diagonalization in revealing inherent limitations of formal systems. They demonstrate that truth in arithmetic outstrips provability, with the halting problem providing a computability-theoretic lens on these limits.^[23] The Church-Turing thesis further bridges these domains by positing that effective computability aligns with provability in formal systems, implying that limits on computation (like undecidability) directly constrain provability. Thus, the thesis ties the halting problem's insolubility to the incompleteness of any sufficiently strong axiomatic theory.

Rice's Theorem Overview

Rice's theorem, established by Henry Gordon Rice in 1953, provides a powerful generalization of the undecidability of the halting problem, asserting that all non-trivial semantic properties of the functions computed by Turing machines are undecidable.^[24] A semantic property concerns the behavior or output of the computed function, independent of the specific syntax or implementation of the machine. Formally, let \phi_e denote the partial recursive function computed by the e-th Turing machine in a standard enumeration. For a set C of partial recursive functions that is neither empty nor the set of all partial recursive functions (i.e., non-trivial), the index set \{ e \mid \phi_e \in C \} is undecidable.^[24] Trivial properties, such as those holding for every partial recursive function (e.g., the function being partial recursive) or for none, yield decidable index sets, but these offer no substantive information about program behavior.^[24] The proof of Rice's theorem proceeds by reduction from the halting problem, specifically the question of whether a given Turing machine halts on the empty tape.^[24] Given a machine M and a non-trivial property C, construct a new machine N that, on any input, first simulates M on the empty tape; if M halts, N then simulates a fixed machine M_0 whose computed function is in C, and otherwise diverges. The index set for C then decides the halting behavior of M on the empty tape, which is impossible unless C is trivial.^[24] This reduction demonstrates that the undecidability inherent in the halting problem propagates to any non-trivial semantic property. Illustrative examples of undecidable properties under Rice's theorem include determining whether a Turing machine computes a total function (i.e., halts on all inputs) or whether it computes the constant zero function.^[24] Another example is verifying if the computed function outputs even values for all inputs, as this defines a non-trivial subset of partial recursive functions.^[24] The implications of Rice's theorem are profound for computability and software engineering, revealing that most interesting questions about program semantics—such as equivalence to a specification, absence of errors, or adherence to non-trivial behavioral constraints—cannot be algorithmically resolved in general.^[24] This foundational result underscores the inherent limitations of automated program analysis and verification tools, which must rely on approximations or restrictions to specific cases to achieve decidability.^[24]

Generalizations

Parameterized Halting

The parameterized halting problem encompasses variations of the standard halting problem where additional parameters, such as fixed inputs or requirements across multiple inputs, are introduced, yet undecidability often persists due to effective reductions from the original problem.^[25] One such variation is the binary halting problem, which asks whether a given Turing machine halts on a specific fixed input, such as the empty tape. This problem remains undecidable, as it can be shown by a mapping reduction from the general halting problem: for an arbitrary machine M and input w, construct a new machine M' that first writes w on the tape and then simulates M on w, starting from the blank tape; M' halts on the blank tape if and only if M halts on w.^[25]^[26] A more demanding parameterization is the totality problem, which determines whether a given Turing machine halts on all possible inputs. This problem is not only undecidable but occupies a higher level in the arithmetic hierarchy, specifically \Pi_2^0-complete, meaning it is as hard as any problem expressible as \forall x \exists y \, R(e, x, y) for a recursive R. To see its undecidability, note that assuming a decider for totality would allow solving the halting problem: given machine M and input w, construct M' that on any input simulates M on w (ignoring its own input) and halts if that simulation halts; then M' halts on all inputs if and only if M halts on w.^[27] In terms of formal complexity classes, the standard halting problem (parameterized by machine and input) is recursively enumerable (RE)-complete, meaning every RE set reduces to it via many-one reduction, while the co-halting problem (non-halting) is co-RE-complete.^[28] These classifications highlight that adding parameters does not resolve undecidability, as computable reductions from the RE-complete halting problem preserve the negative result across variants.^[25]

Oracle and Hypercomputation Models

Oracle machines extend the standard Turing machine model by incorporating an external oracle that provides answers to questions beyond the capabilities of ordinary computation. An oracle machine is a Turing machine augmented with access to an oracle set, which acts as a black box answering membership queries instantaneously. When the oracle set is the halting set—consisting of all pairs (e, x) where Turing machine e halts on input x—the resulting machine can decide the halting problem for all standard Turing machines.^[29] This construction leads to the hierarchy of Turing degrees, which classify sets of natural numbers based on their mutual reducibility via Turing machines. The degree of the halting set, denoted 0', represents the simplest non-recursive degree and is obtained as the Turing jump of the empty set 0; an oracle for 0' enables solving the halting problem, while higher jumps like 0'' address increasingly complex undecidable problems. The theory of Turing degrees, formalized in works building on oracle concepts, demonstrates that undecidability is relative: problems unsolvable in lower degrees become solvable with stronger oracles.^[30] Hypercomputation encompasses theoretical models of computation that surpass the limits of Turing machines, often by invoking infinite processes or non-standard resources, though these remain purely mathematical constructs without physical instantiation. Infinite-time Turing machines (ITTMs) generalize Turing machines to run for transfinite ordinal times, allowing computations to continue through limit stages where the tape state stabilizes after infinitely many steps. ITTMs can solve the halting problem for ordinary Turing machines by simulating them over ordinal time until a halting configuration is reached or a non-halting limit is detected.^[31] Accelerating Turing machines, another hypercomputational model, perform supertasks by completing infinitely many steps in finite real time through successively faster execution rates, akin to Zeno's paradoxes but resolved via acceleration. In this framework, often illustrated with "accelerating turtles" progressing at halving time intervals yet covering infinite computational ground, the machine queries an oracle-like structure at the supertask's completion to decide halting instances that standard machines cannot. These models highlight theoretical extensions but rely on idealized infinite precision and speed.^[32] Zeno machines formalize supertasks explicitly, executing steps in halving time units (e.g., 1/2^n seconds for the nth step) to complete an infinite computation in finite duration, such as one second. A Zeno machine can solve the halting problem by simulating the target Turing machine through all possible steps within the supertask and observing the final state. However, Zeno machines face their own halting problem, as determining whether a Zeno program completes its supertask remains undecidable within the model.^[33] The relativization of the halting problem in these models underscores that undecidability is not absolute but depends on the computational framework: oracles and hypermachines "solve" it by assuming extra power, yet each introduces new undecidable questions at higher levels. Philosophically, the physical realizability of hypercomputation sparks debate, as supertasks like those in Zeno or accelerating models violate constraints of finite energy, space, and time in known physics. The Church-Turing thesis posits that no physically realizable device exceeds Turing-computable functions, critiquing hypercomputation as non-physical and thus irrelevant to effective computation.^[34]

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[PDF] Undecidability [Fa'16] - Jeff Erickson
Turing used this observation about self-reference to derive his first undecidable language as follows. Let's say that a Turing machine M is self-rejecting ...
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[PDF] Turing Machines, diagonalization, the halting problem, reducibility
A Turing machine computing f is called a universal Turing machine. Note that the function f(hMi,x) = M(x) is a partial function, since in this context the given.Missing: encoding | Show results with:encoding
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[PDF] Diagonalization and the Halting Problem
Now apply diagonalization; that is, go down the diagonal and change every Acc to a Not and vice versa. If one writes down all those strings that.
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[PDF] Lecture 21: Undecidability, halting and diagonal- ization
Apr 14, 2009 · In this lecture we will discuss the halting problem and diagonalization. ... Let us show a non-constructive proof that not all languages are ...
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[PDF] Incompleteness via the halting problem - andrew.cmu.ed
Feb 21, 2005 · This is essentially Gödel's version of the first incompleteness theorem. It is stronger than Theorem 2.1 since for one part of the independence ...
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[PDF] Computability theory - UC Berkeley math
Feb 25, 2024 · A modern proof of Gödel's theorem is to show that the halting problem can be reduced to the problem of computing truth for sentences in the ...Missing: implications | Show results with:implications
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[1812.00990] Hilbert's tenth problem, Gödel's incompleteness ... - arXiv
Dec 2, 2018 · Abstract page for arXiv paper 1812.00990: Hilbert's tenth problem, Gödel's incompleteness, Halting problem, a unifying perspective.
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CLASSES OF RECURSIVELY ENUMERABLE SETS AND THEIR ...
H. G. RICE. 1. Introduction. In this paper we consider classes whose elements are re- cursively enumerable sets of non-negative integers.
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[PDF] Undecidability Reductions - Duke Computer Science
(blank-tape halting problem is unsolvable). Proof: Reduce. (halting problem) to. (blank-tape problem). TM. BLANK is undecidable. TM. HALT. TM. BLANK. Prof.
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[PDF] 1 The Halting Problem - UCSD Math
Apr 11, 2012 · The M-w Halting Problem is the set H∗ of pairs (pMq,w). H∗ := {(pMq,w) : M(w) eventually halts.} Theorem 2. The M-w Halting Problem H∗ is ...
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[PDF] Open Problems and Challenges - FSL - · Formal Systems Laboratory
Feb 28, 2016 · Pi_2^0-complete problem, in fact, which makes it theoretically as hard as the totality problem for Turing machines: given a Turing machine ...
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https://arxiv.org/pdf/2211.13532
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[PDF] Complexity of Fractran and Productivity - Jörg Endrullis
Productivity Problem with respect to a family S of computable strategies ... Turing machine M halts on the input n. Note that the rewrite sequence starting.
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[PDF] arXiv:2211.13532v3 [quant-ph] 15 Mar 2023
Mar 15, 2023 · Both problems are undecidable, as the following reduc- tion from the halting problem Halt shows. Theorem 4. NHalt and NHaltAll are RE-complete.
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[PDF] Systems of logic based on ordinals (Proc. Lond. Math. Soc., series 2 ...
Turing considered several natural ways in which ordinal logics could be constructed: (i) A p, obtained by successively adjoining statements directly overcoming ...
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[PDF] Embeddings into the Turing degrees - Berkeley Math
Apr 4, 2007 · The first result in this direction was proved by Kleene and. Post [KP54] in the same paper where they introduced the Turing degrees. They ...
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[PDF] 2006-510.pdf - Queen's School of Computing
Mar 20, 2006 · This paper is a review of one of the most intriguing vehicles that have been proposed to violate the Church-Turing thesis: the accelerating ...
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[PDF] Zeno machines and hypercomputation - arXiv
This paper reviews the Church-Turing Thesis (or rather, theses) with reference to their origin and ap- plication and considers some models of “hypercomputation” ...
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A Brief Critique of Pure Hypercomputation - ResearchGate
Aug 10, 2025 · Some useful information about the physical Church-Turing thesis along with hypercomputation and supertasks can be found in Minsky (1967), Clark ...