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Newton line

In Euclidean geometry, the Newton line of a convex quadrilateral (other than a parallelogram) is the straight line that joins the midpoints of its two diagonals.^[1] This line is named after the English mathematician and physicist Isaac Newton, who first investigated its properties in the late 17th century as part of his work on conic sections and tangential figures.^[1] The requirement that the quadrilateral not be a parallelogram ensures the midpoints are distinct, as the diagonals of a parallelogram intersect at their common midpoint.^[2] One of the most notable properties of the Newton line arises in the context of tangential quadrilaterals, which are convex quadrilaterals admitting an inscribed circle tangent to all four sides. Newton's quadrilateral theorem states that if a circle is tangent to the four extended sides of such a quadrilateral, then the center of the circle lies on the Newton line.^[1] This theorem holds for both convex and certain non-convex quadrilaterals, provided the tangency conditions are satisfied, and it can be proved using methods such as signed areas or vector geometry.^[3] Additionally, the vertex centroid of the quadrilateral (the average of its four vertices) bisects the segment of the Newton line between the diagonal midpoints.^[2] The significance of the Newton line extends beyond circles through generalizations involving conic sections. For any non-parallelogram quadrilateral, the centers of all ellipses or hyperbolas tangent to its four extended sides lie on the Newton line, providing a locus for infinitely many such conics (in contrast to the unique incircle).^[1] A converse result further characterizes the line: every point on the Newton line, except for three singular points corresponding to degenerate cases, serves as the center of some tangent ellipse or hyperbola to the quadrilateral.^[1] These properties highlight the Newton line's role in projective and affine geometry, linking it to broader theorems on quadrilaterals and conics, including dual forms for complete quadrilaterals where midpoints of diagonal segments are collinear on a related Newton-Gauss line.^[4]

Definition and History

Definition

A convex quadrilateral is a four-sided polygon in which all interior angles are less than 180 degrees and both diagonals lie entirely within the figure. In such a quadrilateral ABCD, no three sides meet at a single point, ensuring it is simple and non-degenerate, and it has at most two parallel sides to avoid cases like parallelograms where certain lines degenerate.^[5] The diagonals of quadrilateral ABCD are the line segments AC and BD, connecting opposite vertices.^[6] The midpoint of a diagonal, such as AC with endpoints at coordinates (x_1, y_1) and (x_2, y_2), is the point E = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right), calculated as the average of the coordinates; similarly for midpoint F of BD.^[7] The Newton line of convex quadrilateral ABCD is defined as the straight line passing through these midpoints E on AC and F on BD.^[5] For illustration, consider points A, B, C, D forming the quadrilateral; mark E as the midpoint of diagonal AC and F as the midpoint of diagonal BD; the Newton line is then the line through these points.^[6]

Historical Background

The concept of the Newton line originates from Isaac Newton's geometric investigations in the late 17th century, as presented in his Philosophiæ Naturalis Principia Mathematica (1687), particularly in Book I, Section V, where he demonstrated properties of conics tangent to the sides of a quadrilateral, showing that their centers lie on the line connecting the midpoints of the diagonals.^[3] This work built on Newton's earlier studies in the 1660s and 1670s on conics and curves, influenced by classical geometers like Apollonius, though the specific result appeared in his published Principia, amid broader developments in analytic methods and projective elements alongside his work in calculus and optics.^[8] The line gained further recognition in the early 19th century through Carl Friedrich Gauss's independent contributions to quadrilateral geometry, where he examined collinearity properties in more complex figures, contributing to the dual naming as the Newton-Gauss line for complete quadrilaterals. Jakob Steiner popularized and ascribed the core result to Newton in his 1828 note on the complete quadrilateral, framing it within projective geometry challenges and confirming the midpoints' collinearity via synthetic proofs.^[9] Although the theorem appeared in Newton's 1687 Principia, it was referenced in subsequent geometry texts discussing tangential quadrilaterals and incircle centers. By the 20th century, the Newton line received formal nomenclature in analytic geometry literature, including 1930s treatises on projective configurations that integrated vector and coordinate approaches to generalize it from simple convex quadrilaterals to complete ones. This evolution underscored its role in bridging Euclidean and projective frameworks, with applications in conic loci and midpoint theorems persisting in modern geometric analysis.^[10]

Geometric Properties

Bimedians and Varignon Configuration

In a quadrilateral ABCD, the bimedians are the line segments connecting the midpoints of opposite sides: one joins the midpoint of side AB to the midpoint of side CD, while the other joins the midpoint of side AD to the midpoint of side BC.^[11] These two bimedians intersect at a single point K, which serves as their common midpoint and the centroid (or barycenter) of the quadrilateral's vertices, assuming equal masses at each vertex.^[11]^[2] In vector notation, if \mathbf{A}, \mathbf{B}, \mathbf{C}, and \mathbf{D} denote the position vectors of the vertices, the centroid K is given by

\mathbf{K} = \frac{\mathbf{A} + \mathbf{B} + \mathbf{C} + \mathbf{D}}{4}.

This point K divides each bimedian in the ratio 1:1.^[11] The Varignon parallelogram arises from connecting the midpoints of the sides of quadrilateral ABCD, forming a parallelogram by Varignon's theorem regardless of the original quadrilateral's shape.^[12] The diagonals of this Varignon parallelogram are exactly the bimedians of ABCD, so their intersection is again the centroid K.^[11]^[12] The Newton line, which joins the midpoints E and F of the diagonals AC and BD, passes through the centroid K and bisects the segment EF in the ratio 1:1, thereby integrating the bimedian configuration into the quadrilateral's midline structure.^[11] This positioning highlights K as a central point balancing both the side midpoints and diagonal midpoints.^[13]

Anne's Theorem

Anne's theorem states that in a convex quadrilateral ABCD that is not a parallelogram, for any point P on the Newton line, the sum of the areas of triangles ABP and CDP equals the sum of the areas of triangles ADP and BCP, i.e., [ABP] + [CDP] = [ADP] + [BCP].^[14] This equality holds because the total area of the quadrilateral is partitioned into these four triangles, making each pair sum to half the total area.^[15] A proof can be obtained using coordinate geometry by assigning coordinates to the vertices A, B, C, D and placing the Newton line along the x-axis for simplicity; the areas are then computed using the shoelace formula, and the condition [ABP] + [CDP] = [ADP] + [BCP] simplifies to a linear equation in the coordinates of P, confirming that the locus is indeed the straight line joining the midpoints of the diagonals. Alternatively, a geometric proof leverages the fact that medians bisect triangle areas, showing that points on the line through the diagonal midpoints satisfy the area balance due to the bimedians' intersection properties.^[14] Geometrically, the theorem characterizes the Newton line as a "balance line" where the areas of triangles formed by connecting a point on the line to opposite sides of the quadrilateral are equal, providing a way to identify the line without directly computing midpoints.^[16] For illustration, consider quadrilateral with vertices A(0,0), B(3,0), C(2,2), D(0,1). The midpoints of diagonals AC and BD are (1,1) and (1.5,0.5), respectively, so the Newton line has equation y = -x + 2. For point P(1,1) on this line, [ABP] = 1.5, [CDP] = 0.5, [ADP] = 0.5, and [BCP] = 1.5, verifying the equality. The theorem is named after the French mathematician Pierre-Léon Anne (1806–1850), who formulated it in the 19th century as an extension of ideas related to quadrilateral properties explored since Newton.^[14]

Theorems and Applications

Newton's Theorem

A tangential quadrilateral is a convex quadrilateral that possesses an incircle tangent to all four of its sides. This geometric configuration is possible if and only if the sums of the lengths of the opposite sides are equal, denoted as a + c = b + d, where a, b, c, and d are the successive side lengths.^[14] Newton's theorem asserts that, in a tangential quadrilateral that is not a rhombus, the incenter I—defined as the center of the incircle and the intersection of the internal angle bisectors—lies on the Newton line, which is the line segment EF joining the midpoints E and F of the two diagonals.^[3] In the special case of a rhombus, the midpoints of the diagonals coincide at the center of the quadrilateral, which also serves as the incenter, rendering the Newton line degenerate to a point while still satisfying the theorem trivially.^[14] A proof sketch relies on the equal tangent lengths from each vertex to the points of tangency and the resulting area balance. Let the tangent lengths from vertices A, B, C, and D be s, t, u, and v respectively, so the side lengths are AB = s + t, BC = t + u, CD = u + v, and DA = v + s. The incircle with radius r divides the quadrilateral into four triangles from I to the vertices, with areas \frac{1}{2} r times each side length. The sums of the areas of opposite triangles are then \frac{1}{2} r (AB + CD) = \frac{1}{2} r (s + t + u + v) and \frac{1}{2} r (BC + DA) = \frac{1}{2} r (t + u + v + s), which are equal due to the tangential condition. This equality implies that I satisfies the condition of Anne's theorem, where the locus of points O such that the sum of areas of triangles AOB and COD equals the sum of areas of BOC and AOD is precisely the Newton line.^[14] In coordinate geometry, the alignment can be verified by deriving the incenter's position and showing it satisfies the equation of the line through E and F. For a tangential quadrilateral with vertices at coordinates A(0,0), B(1,0), C(p_1, p_2), and D(0,1), the midpoints yield the Newton line parameterized such that the center I (solving the equidistance to sides) lies on it, as the tangency conditions lead to linear equations placing I on the line defined by the midpoints.^[1] More generally, the incenter's coordinates form a weighted average of the vertex positions by the side lengths, I = \frac{aA + bB + cC + dD}{a + b + c + d}, where the weights correspond to the adjacent side influences, ensuring collinearity with the midpoint line under the tangential constraint.^[17] This theorem finds applications in geometric problems requiring the relative positioning of the incenter and diagonals, such as constructing incircles or analyzing midline properties in tangential figures.^[18]

Extensions to Cyclic and Other Quadrilaterals

In cyclic quadrilaterals, where the vertices lie on a common circle and opposite angles sum to 180°, the Newton line exhibits specific relations, particularly when the quadrilateral is also tangential, forming a bicentric quadrilateral. A tangential quadrilateral is bicentric if and only if its Newton line is perpendicular to the Newton line of its contact quadrilateral, the quadrilateral formed by the points of tangency of the incircle.^[19] For bicentric quadrilaterals, which possess both an incircle and a circumcircle, the incenter lies on the Newton line, extending the property from purely tangential cases. Additionally, the incenter, circumcenter, and the intersection point of the diagonals are collinear, though the circumcenter does not necessarily lie on the Newton line itself.^[20] In trapezoids, which have exactly one pair of parallel sides (the bases), the Newton line is parallel to these bases. This holds regardless of whether the trapezoid is isosceles. For example, consider an isosceles trapezoid with vertices at A(0,0), B(3,0), C(2,2), and D(1,2). The diagonals are AC with midpoint (1,1) and BD with midpoint (2,1). The Newton line joining these midpoints is the horizontal line y=1, parallel to the bases at y=0 and y=2.^[1] This parallelism in trapezoids represents a generalization of the Newton line's behavior in quadrilaterals with parallel sides, where the line aligns with the direction of the parallelism, passing through additional conic centers tangent to the extended sides. In kites, which have two pairs of adjacent equal sides and a line of symmetry along one diagonal (the symmetry diagonal), the intersection of the diagonals is the midpoint of the other diagonal (the cross diagonal). The Newton line thus lies along the symmetry diagonal, joining its own midpoint to this intersection point.^[1]

Newton-Gauss Line

A complete quadrilateral is a configuration formed by four lines in the plane, no three of which are concurrent, yielding six points of intersection. These six points serve as vertices, and the three diagonals are the lines connecting pairs of opposite vertices (i.e., intersection points not lying on the same original line). This setup contrasts with a simple quadrilateral, which involves four points and their connecting segments, by emphasizing the lines rather than the points as primitives.^[21] The Newton-Gauss line of a complete quadrilateral is the line that passes through the midpoints of its three diagonals. The Newton-Gauss theorem states that these three midpoints are always collinear, forming this line, provided the four lines are in general position (no two parallel, to ensure finite intersections). This collinearity holds in the Euclidean plane and extends to projective geometry. The theorem was established by Isaac Newton in the context of quadrilateral properties and formalized by Carl Friedrich Gauss in the early 19th century, highlighting the midpoints' alignment as a fundamental geometric invariant.^[10]^[22] In relation to the Newton line of a simple convex quadrilateral, which joins the midpoints of its two internal diagonals, the Newton-Gauss line represents a generalization. For a convex quadrilateral with no parallel sides, the four sides form a complete quadrilateral, where the two internal diagonals and the line joining the intersection points of opposite sides constitute the three diagonals. The midpoints of all three lie on the same line, so the Newton line coincides with the Newton-Gauss line in this case. If opposite sides are parallel, the third diagonal is at infinity, and its midpoint is also at infinity, preserving collinearity projectively but degenerating the configuration. Thus, the simple Newton line always exists for any quadrilateral, while the full Newton-Gauss line requires the general position of four lines to manifest three finite diagonals.^[21]^[10] The collinearity can be proven using vector geometry. Label the intersection points of the four lines as A, B, C, D, E, F, where the diagonals are, say, AC, BE, and DF. The position vectors of the midpoints are M = \frac{\vec{A} + \vec{C}}{2}, N = \frac{\vec{B} + \vec{E}}{2}, and P = \frac{\vec{D} + \vec{F}}{2}. Due to the linear dependencies imposed by the lines (e.g., points on each line satisfy affine relations), the vectors satisfy \vec{P} = (1 - t) \vec{M} + t \vec{N} for some scalar t, confirming they lie on a parametric line. Alternatively, projective proofs employ properties like Desargues' theorem or cross-ratios to establish the alignment invariantly under perspective transformations.^[10]

Representations in Coordinate Geometry

In coordinate geometry, a convex quadrilateral ABCD is defined by assigning coordinates to its vertices: A(x₁, y₁), B(x₂, y₂), C(x₃, y₃), and D(x₄, y₄).^[23] The midpoints of the diagonals AC and BD are calculated as E = \left( \frac{x_1 + x_3}{2}, \frac{y_1 + y_3}{2} \right) for AC and F = \left( \frac{x_2 + x_4}{2}, \frac{y_2 + y_4}{2} \right) for BD.^[23] The Newton line is the straight line passing through these midpoints E and F.^[6] The equation of the Newton line in two-point form is given by

\frac{y - y_E}{y_F - y_E} = \frac{x - x_E}{x_F - x_E},

assuming y_F ≠ y_E and x_F ≠ x_E; otherwise, the line is horizontal or vertical, respectively.^[6] In vector notation, the Newton line consists of all points of the form (1 - t) \mathbf{E} + t \mathbf{F}, where t is a real parameter and \mathbf{E}, \mathbf{F} are the position vectors of the midpoints.^[24] To verify the representation, consider the centroid G of the quadrilateral, defined as G = \left( \frac{x_1 + x_2 + x_3 + x_4}{4}, \frac{y_1 + y_2 + y_3 + y_4}{4} \right). This point coincides with the midpoint of segment EF, confirming that G lies on the Newton line.^[6] For a concrete example, take the tangential quadrilateral with vertices A(0, 0), B(40, 9), C(36, 12), and D(35, 12). The midpoint E of AC is (18, 6), and F of BD is (37.5, 10.5). The centroid G is (27.75, 8.25), which lies on the line through E and F, as substituting into the parametric form yields t = 0.5 for G.^[24] These coordinate representations facilitate computational applications, such as verifying collinearity in geometric software or analyzing quadrilateral properties through vector calculations.^[6]

References

[1]
[PDF] A generalization of Newton's quadrilateral theorem and an ... - arXiv
Nov 17, 2022 · If Q is a convex quadrilateral, the set of centers of all conics passing through the four vertices of Q is a hyperbola; if Q is not convex, this ...Missing: Isaac | Show results with:Isaac
[2]
Definitions and Hierarchy of Quadrilaterals - UTSA
Dec 12, 2021 · Another remarkable line in a convex non-parallelogram quadrilateral is the Newton line, which connects the midpoints of the diagonals, the ...
[3]
[PDF] Newton's Quadrilateral Theorem - AwesomeMath
May 15, 2023 · This means point 𝑋 lies in a line parallel to line 𝐾𝐿. 2. Proof of Newton's Theorem for a circle. We are ready to prove Newton's Theorem ...
[4]
(PDF) On the Newton line of a quadrilateral - ResearchGate
May 25, 2016 · Specializing for quadrangles we prove a characterization of their Newton line related to the possibility to inscribe a quadrangle having its ...
[5]
Newton line - Applied Mathematics Consulting
Oct 14, 2023 · Draw the two diagonals then draw a line through their midpoints. This line is called the Newton line.Missing: definition | Show results with:definition
[6]
Quadrilateral -- from Wolfram MathWorld
Given any five points in the plane in general position, four will form a convex quadrilateral. ... " §91-92 in Modern Geometry: An Elementary Treatise on the ...
[7]
Midpoint formula | Analytic geometry (article) - Khan Academy
You add the two x-values and divide by 2. You add the two y-values and divide by 2. This gives you the coordinates of the midpoint (the point located half-way ...
[8]
[PDF] newton, the geometer - Stephen Huggett
Isaac Newton was a geometer. Although he is much more widely known for the calculus, the inverse square law of gravitation, and the optics, geometry lay at the ...
[9]
Steiner's Theorems on the Complete Quadrilateral - ResearchGate
... Steiner's 1828 note on the complete quadrilateral, with complete ... In addition, we discuss its relation to the Newton line of a complete quadrilateral ...<|control11|><|separator|>
[10]
[PDF] The converse of the Newton-Gauss theorem
The famous Newton-. Gauss theorem asserts that the midpoints of the diagonals of any complete quadrilateral are collinear. The line on which these midpoints sit ...
[11]
Bimedians in a Quadrilateral
The median EF -- the line joining the midpoints of the diagonals of a quadrlateral -- is also known as its Newton's line [F. G.-M., p. 767]. The line appears in ...
[12]
Simple Quadrilaterals - Every truth has four corners
But the bimedians are the diagonals of the. Varignon parallelogram, and hence bisect one another, intersecting at a common midpoint. This intersection point 0, ...
[13]
[PDF] Untitled
segment connecting the diagonals of a quadrilateral bisects both diagonals, then this line segment (the Newton Line) is itself bisected by the vertex centroid.
[14]
Newton's Theorem and Leon Anne's Theorem
Newton's theorem: The center of the circle inscribed into a quadrilateral lies on the line joining the midpoints of the latter's diagonals.<|control11|><|separator|>
[15]
Léon Anne's Theorem -- from Wolfram MathWorld
Pick a point O in the interior of a quadrilateral which is not a parallelogram. Join this point to each of the four vertices.
[16]
[PDF] Balanced areas in quadrilaterals – on the way to Anne's Theorem
This article gives an example for using Dynamic Geometry Software to encourage making conjectures, reasoning, and experiencing mathematics as a process.
[17]
Proof of Newton's theorem for tangential quadrilaterals
Jul 12, 2018 · Newton's Theorem for tangential quadrilaterals is this: The center of the circle inscribed into a quadrilateral lies on the line joining the midpoints of the ...Prove that 5 lines are concurrent - Math Stack ExchangeCartesian formula for incenter of tangential quadrilateral from ...More results from math.stackexchange.com
[18]
(PDF) Vectorial Proof of Newton's Quadrilateral Theorem
Nov 5, 2023 · We use symplectic geometry to proof Newton's famous quadrilateral theorem, which states, that if a quadrilateral has an incircle, ...
[19]
Characterizations of Bicentric Quadrilaterals - ResearchGate
According to one of these, a tangential quadrilateral is cyclic if and only if its Newton line is perpendicular to the Newton line of its contact quadrilateral.
[20]
None
### Summary of Newton Line Properties in Bicentric Quadrilaterals
[21]
Complete Quadrilateral -- from Wolfram MathWorld
A complete quadrilateral has three diagonals (compared to two for an ordinary quadrilateral). The midpoints of the diagonals of a complete quadrilateral are ...<|control11|><|separator|>
[22]
Theorem of Complete Quadrilateral
The line is commonly known as the Newton-Gauss line. Below I give two proofs of the Theorem of Complete Quadrilateral.
[23]
Prove that the line joining the midpoints of the opposite sides... | Filo
Jul 2, 2025 · Now, find the midpoints of the diagonals AC and BD. Let N1 be the midpoint of AC and N2 be the midpoint of BD. N1 = ((x1 + x3)/2, (y1 + y3)/2 ...
[24]
[PDF] A48 INTEGERS 23 (2023) LATTICE EQUABLE QUADRILATERALS III
Jun 30, 2023 · Let MA,MO denote the midpoint of the diagonals AC, OB, respectively; see Figures 3 and 4. Notice that MA,MO are distinct, and the Newton line ...